题目:Max Points on a line Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 这道题需要稍微转变一下思路,用斜率来实现,试想找在同一条直线上的点,怎么判断在一条直线上,唯一的方式也只有斜率可以完成,我开始没想到,后来看网友的思路才想到的,下面是简单的实现:其中有一点小技巧,利用map<double, int>来存储具有相同斜率
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. /** * Definition for a point. * struct Point { * int x; * int y; * Point() : x(0), y(0) {} * Point(int a, int b) : x(a), y(b) {} * }; */ class Solutio
Lining Up Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 1274 Accepted Submission(s): 366 Problem Description ``How am I ever going to solve this problem?" said the pilot. Indeed, the pilo
/** * Definition for a point. * struct Point { * int x; * int y; * Point() : x(0), y(0) {} * Point(int a, int b) : x(a), y(b) {} * }; */ class Solution { public: /** * @param points an array of point * @return an integer */ int maxPoints(vector<Point
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. Example 1: Input: [[1,1],[2,2],[3,3]] Output: 3 Explanation: ^ | | o | o | o +-------------> 0 1 2 3 4 Example 2: Input: [[1,1],[3,2]
给定二维平面上有 n 个点,求最多有多少点在同一条直线上. 详见:https://leetcode.com/problems/max-points-on-a-line/description/ Java实现: /** * Definition for a point. * class Point { * int x; * int y; * Point() { x = 0; y = 0; } * Point(int a, int b) { x = a; y = b; } * } */ class
直线上最多的点数 给定一个二维平面,平面上有 n 个点,求最多有多少个点在同一条直线上. 示例 1: 输入: [[1,1],[2,2],[3,3]] 输出: 3 解释: ^ | | o | o | o +-------------> 0 1 2 3 4 示例 2: 输入: [[1,1],[3,2],[5,3],[4,1],[2,3],[1,4]] 输出: 4 解释: ^ | | o | o o | o | o o +-----------
给定一个二维平面,平面上有 n 个点,求最多有多少个点在同一条直线上. 示例 1: 输入: [[1,1],[2,2],[3,3]] 输出: 3 解释: ^ | | o | o | o +-------------> 0 1 2 3 4 示例 2: 输入: [[1,1],[3,2],[5,3],[4,1],[2,3],[1,4]] 输出: 4 解释: ^ | | o | o o | o | o o +------------------
You are given n points on Cartesian plane. Every point is a lattice point (i. e. both of its coordinates are integers), and all points are distinct. You may draw two straight lines (not necessarily distinct). Is it possible to do this in such a way t
public static void main(String[] args) { Scanner scan = new Scanner(System.in); Point point1 = new Point(); Point point2 = new Point(); double x, y; point1.setLocation(5.0, 5.0); point2.setLocation(1.0, 1.0); System.out.println("请分别输入点x,y的坐标:");
You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13549 Accepted Submission(s): 6645 Problem Description Many geometry(几何)problems were designed in the ACM/
