http://www.digitalsolutionslab.com/installing-quartus-ii-v-13-1-64-bit-on-rhelcentos-6-64-bit/ I have been using Quartus II v.12.1 on RHEL 5 and decided that going through the installation procedure for the Quartus II v.13.1 on an updated RHEL (namel
当A是一个列向量时候,返回一个最大值,在此不在赘述. 当Amxn是一个矩阵的时候,有以下几种情况: ① C = max(max(A)),返回矩阵最大值 ② D = max(A,[],1),返回每一行的最大值,即mx1的行向量 ③ E = max(A,[],2),返回每一列的最大值,即1xm的列向量 ④ F = max(A,8),当元素小于8,用8填充 ⑤ [U V] = max(A),返回行列最大元素的行号与列号 注意以下几个表达式: H = max(A) I = max(A
count 用法 求总条数 $sql="select count(*) as total from e_user"; $query = mysql_query($sql, $link); $res = mysql_fetch_array($query); $count = $res['total']; max用法 $sql="select max(id) as maxid from e_user"; $sql="select id as maxid fro
A. Donut 扫描线+线段树. #include<cstdio> #include<algorithm> using namespace std; typedef long long ll; const int N=800010,M=2222222; int n,m,cnt,i,j;ll L,R,D,a[N]; int tag[M],v[M],ans; struct E{ ll x,l,r;int s; E(){} E(ll _x,ll _l,ll _r,int _s){x=_
A. Pieces of Parentheses 将括号串排序,先处理会使左括号数增加的串,这里面先处理减少的值少的串:再处理会使左括号数减少的串,这里面先处理差值较大的串.确定顺序之后就可以DP了. 时间复杂度$O(n^3)$. #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int N=310,inf=1000000; int n,i,j,m,all,
-- return the index of max number and himself -- 函数可以返回多个值 function get_max( T ) ] for i, v in ipairs( T ) do if v > max then max = v index = i end end return index, max end -- 如果函数的参数为表或者字符串 可以省略小括号 -- index, value = get_max{ 10, 1, -1, 0, 3, 20, 9,
题目: Problem D. Great AgainInput file: standard inputOutput file: standard outputTime limit: 2 secondsMemory limit: 512 megabytesThe election in Berland is coming. The party United Berland is going to use its influence to win themagain. The crucial co