这是个很诡异的问题,由于一些特殊需求,我的TableView的Cell的背景色是透明,其中的控件会有背景色,第一个控件和最后一个控件我都用IB自动设了约束,对齐Cell的左边界和右边界,但是自动约束很奇怪的是值都是-8(上下左右都是这个值).一开始并没在意因为显示出来是好的,但是不记得升级SDK到8.2还是8.3开始,左右就会多出空白来. 经过各种尝试,找到了解决方法.将左右的约束中item的related to margin(印象中是这么拼)取消勾选,值设为0就好了. 下班了等人,mac关了没
Given a set of intervals, for each of the interval i, check if there exists an interval j whose start point is bigger than or equal to the end point of the interval i, which can be called that j is on the "right" of i. For any interval i, you ne
Follow up for problem "Populating Next Right Pointers in Each Node". What if the given tree could be any binary tree? Would your previous solution still work? Note: You may only use constant extra space. For example,Given the following binary tr
Given a binary tree struct TreeLinkNode { TreeLinkNode *left; TreeLinkNode *right; TreeLinkNode *next; } Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL. Initially, al
记录备忘下,初始数据如下: DROP TABLE IF EXISTS t_demo_product; CREATE TABLE IF NOT EXISTS t_demo_product( proid ), proname ), price ), PRIMARY KEY(proid) )ENGINE=InnoDB DEFAULT CHARSET=gbk; DROP TABLE IF EXISTS t_demo_operation; CREATE TABLE IF NOT EXISTS t_demo
C指针声明解读之左右法则 C语言所有复杂的指针声明,都是由各种声明嵌套构成的.如何解读复杂指针声明呢?右左法则是一个既著名又常用的方法.不过,右左法则其实并不是C标准里面的内容,它是从C标准的声明规定中归纳出来的方法.C标准的声明规则,是用来解决如何创建声明的,而右左法则是用来解决如何辩识一个声明的,两者可以说是相反的.右左法则的英文原文是这样说的: The right-left rule: Start reading the declaration from the innermost par
Left Join / Right Join /inner join相关 关于左连接和右连接总结性的一句话: 左连接where只影向右表,右连接where只影响左表. Left Join select * from tbl1 Left Join tbl2 where tbl1.ID = tbl2.ID 左连接后的检索结果是显示tbl1的所有数据和tbl2中满足where 条件的数据. 简言之 Left Join影响到的是右边的表 Right Join select * from tbl1 Rig
