函数reduce,lambda,filter

 #比较时间差，判断执行有时。

 import time
 def panduan(x):
     if x%5==0 and x%7==0:
         return True
     else:
         return  False
 start_time=time.time()
 print reduce((lambda x,y:x+y),filter(panduan,range(1001)))
 end_time=time.time()
 print end_time-start_time

 sum=0
 start_time1=time.time()
 for i in range(1001):
     if i%5==0 and i%7==0:
         sum=sum+i
 print sum
 end_time1=time.time()
 print end_time1-start_time1

 #执行结果
 #
 #0.00799989700317
 #
 #0.00500011444092

两种方法执行1000以内即被5又被7整除的数的和，比较执行所需时间