Problem description

One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12
15
23
1000000

Output

4 8
6 9
8 15
500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

解题思路:每个不小于12的整数可以表示为两个合成数之和,若满足条件有多组,则输出其中的一组,简单判断即可。

AC代码:

 #include<bits/stdc++.h>
using namespace std;
bool isprime(int x){
for(int i=;i*i<=x;++i)
if(x%i==)return false;
return true;
}
int main(){
int n;cin>>n;
for(int i=;;i+=)
if(!isprime(n-i)){cout<<i<<' '<<(n-i)<<endl;break;}
return ;
}

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