百万年薪python之路 -- 模拟三次账号登录锁定功能

用代码实现三次用户登录及锁定(选做,时间充足建议做一做)
项目分析:
一.首先程序启动,显示下面内容供用户选择:
1.注册
2.登录

a.用户选择登录的时候,首先判断用户名在userinfo.txt表中存在不在,存在就不能进行注册
b.当注册的用户名不存在的时候将用户名和密码写入到userinfo.txt文件中
c.用户选择登录的时候,判断用户输入的账号和密码是否userinfo.txt存储的一致
d.用户名和密码一致就终止循环,并提示用户登录成功!
e.用户名和密码不一致,只有三次登录机会,三次过后提示用户名被锁定,请联系管理员!并终止循环
f.当用户名输出三次,再次运行程序.登录锁定的账号继续提示用户名被锁定,请联系管理员!

import os
count = 0
dic = {}
def locked(login_user,count = 3):
    with open("userinfo.txt", "r", encoding="UTF-8") as f4, open("userinfo_bak.txt", "w", encoding="UTF-8") as f5:
        for i in f4:
            i = i.strip().split(":")
            if i[0] == login_user:
                i[0] = i[0].replace(i[0], i[0] + "$")
            f5.write(f"{i[0]}:{i[1]}\n")
    # print(f"你输错了{count}次!")
    print(f"检测到用户名{login_user}已经输错了{count}次,已锁定!请联系管理员!")
    os.remove("userinfo.txt")
    os.rename("userinfo_bak.txt", "userinfo.txt")
def user_login_count(login_user):
    with open("userinfo.txt", "r", encoding="UTF-8") as f:
        for i in f:
            i = i.strip().split(":")
            if i[0][-1] == "$" and i[0][0:-1] == login_user:
                dic[login_user] = 3
    if dic.get(login_user,0) != 3:
        dic[login_user] = dic.get(login_user,0) + 1
    # print(dic[login_user])
    return dic[login_user]
def register():
    user = input("请输入注册用户名(退出程序请按q/Q):")
    if user.lower() == "q":
        return "q"
    while 1:
        pwd = input("请输入注册密码:")
        if not pwd.strip():
            print("注册密码不能为空!请重新输入!")
        else:
            break
    with open("userinfo.txt", "r", encoding="UTF-8") as f:
        flag = True
        for i in f:
            i = i.split(":")
            if user == i[0]:
                print("用户名已存在!")
                flag = False
        if flag == True:
            with open("userinfo.txt", "a", encoding="UTF-8") as f1:
                f1.write(user + ":" + pwd + "\n")
                print("注册成功!")
def login():
    flag = False
    while 1:
        login_user = input("请输入登录用户名(退出程序请按q/Q):")
        if login_user.lower() == "q":
            return "q"
        login_pwd = input("请输入登录密码:")
        with open("userinfo.txt","r",encoding="UTF-8") as f:
            for i in f:
                i = i.strip().split(":")
                if i[0][-1] == "$" and i[0][0:-1] == login_user:
                    print(f"用户名{login_user}已被锁!")
                    break
                elif i[0] == login_user and i[1] == login_pwd:
                    flag = True
                    break
        if flag != True:
            ret = user_login_count(login_user)
            if ret == 3:
                locked(login_user)
            else:
                print(f"登陆失败,你已经输错{ret}次了!")
        else:
            print("登陆成功!")
            dic[login_user] = 0
            break
while 1:
    inp = input("请输入序号(1/注册,2/登录,q或Q/退出程序):")
    if inp == "1" or inp == "2" or inp.lower() == "q":
        if inp == "1":
            if register() == "q":
                break
        elif inp == "2":
            if login() == "q":
                break
        elif inp.lower() == "q":
            print("已退出程序!")
            break
    else:
        print("请重新输入!")