The Hardest Problem Ever

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 13035    Accepted Submission(s): 5905

Problem Description
Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was keeping himself alive. In order for him to survive, he decided to create one of the first ciphers. This cipher was so incredibly sound, that no one could figure it out without knowing how it worked. 
You are a sub captain of Caesar's army. It is your job to decipher the messages sent by Caesar and provide to your general. The code is simple. For each letter in a plaintext message, you shift it five places to the right to create the secure message (i.e., if the letter is 'A', the cipher text would be 'F'). Since you are creating plain text out of Caesar's messages, you will do the opposite:

Cipher text
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

Plain text
V W X Y Z A B C D E F G H I J K L M N O P Q R S T U

Only letters are shifted in this cipher. Any non-alphabetical character should remain the same, and all alphabetical characters will be upper case.

 
Input
Input to this problem will consist of a (non-empty) series of up to 100 data sets. Each data set will be formatted according to the following description, and there will be no blank lines separating data sets. All characters will be uppercase.

A single data set has 3 components:

Start line - A single line, "START"

Cipher message - A single line containing from one to two hundred characters, inclusive, comprising a single message from Caesar

End line - A single line, "END"

Following the final data set will be a single line, "ENDOFINPUT".

 
Output
For each data set, there will be exactly one line of output. This is the original message by Caesar.
 
Sample Input
START
NS BFW, JAJSYX TK NRUTWYFSHJ FWJ YMJ WJXZQY TK YWNANFQ HFZXJX
END
START
N BTZQI WFYMJW GJ KNWXY NS F QNYYQJ NGJWNFS ANQQFLJ YMFS XJHTSI NS WTRJ
END
START
IFSLJW PSTBX KZQQ BJQQ YMFY HFJXFW NX RTWJ IFSLJWTZX YMFS MJ
END
ENDOFINPUT
 
Sample Output
IN WAR, EVENTS OF IMPORTANCE ARE THE RESULT OF TRIVIAL CAUSES
I WOULD RATHER BE FIRST IN A LITTLE IBERIAN VILLAGE THAN SECOND
IN ROME
DANGER KNOWS FULL WELL THAT CAESAR IS MORE DANGEROUS THAN HE
 
Source
 
此题为简单的字符串处理问题....
但是要注意数组开大点....1000足矣;
 #include<iostream>
#include<cstring>
#include<cstdlib>
char str[]="VWXYZABCDEFGHIJKLMNOPQRSTU";
char a[];
int main()
{
int i;
// freopen("test.in","r",stdin);
// freopen("test.out","w",stdout);
while(scanf("%[^\n]",a)!=EOF)
{
if(strcmp("ENDOFINPUT",a)==)
break;
if(strcmp("START",a)!=&&strcmp("END",a)!=)
{
for(i=;i<strlen(a);i++)
{
if(a[i]>='A'&&a[i]<='Z')
printf("%c",str[a[i]-'A']);
else
printf("%c",a[i]);
}
puts("");
}
a[]=;
getchar();
}
return ;
}
 

HDUOJ-------The Hardest Problem Ever的更多相关文章

  1. HDU1048The Hardest Problem Ever

    The Hardest Problem Ever Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & ...

  2. The Hardest Problem Ever(字符串)

    The Hardest Problem Ever Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24039   Accept ...

  3. (字符串 枚举)The Hardest Problem Ever hdu1048

    The Hardest Problem Ever 链接:http://acm.hdu.edu.cn/showproblem.php?pid=1048 Time Limit: 2000/1000 MS ...

  4. hdu_1048_The Hardest Problem Ever_201311052052

    The Hardest Problem Ever Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java ...

  5. HDOJ 1048 The Hardest Problem Ever(加密解密类)

    Problem Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caes ...

  6. C - The Hardest Problem Ever

    Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever ...

  7. POJ 1298 The Hardest Problem Ever【字符串】

    Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was ke ...

  8. Poj1298_The Hardest Problem Ever(水题)

    一.Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar eve ...

  9. poj1298 The Hardest Problem Ever 简单题

    链接:http://poj.org/problem?id=1298&lang=default&change=true 简单的入门题目也有这么强悍的技巧啊!! 书上面的代码: 很厉害有没 ...

随机推荐

  1. 移动前端调试工具-Weinre真机调试

    之前做移动前端调试页面的时候就是简单的使用Chrome模拟器调试,能满足基本基本的需求,后来发现了基于Web Inspector(Webkit)的远程调试工具Weinre,可以在PC端直接调试运行在移 ...

  2. 前端开发必备 40款优秀CSS代码编写工具推荐

    摘要:CSS工具可以简化工作流,可以提高CSS编写速度,是开发者和设计者所不可缺少的.本文列举了40种CSS工具,功能涉及CSS菜单.动画.3D图形.响应式页面.图层.按钮等界面元素的设计与制作,你定 ...

  3. redis信息相关集群

    转: http://www.runoob.com/redis/redis-install.html //redis的安装与运维相关 http://zhou123.blog.51cto.com/4355 ...

  4. CSS3提交意见输入框样式

    做了个输入框样式,如图: CSS代码例如以下: #button { cursor:pointer; width:30%; margin:5px; padding:8px; border-radius: ...

  5. C++ 多态的原理

    1.多态解决什么问题? 面向抽象编程,用户不需要关心引用或者指针的真实类型,已经内部实现.2.C++ 要具备多态的性质,满足两个条件:表面类型和真实类型不一样,方法是虚方法.3.多态是如何实现的? 实 ...

  6. Code faster with Intellij IDEA live templates

    Intellij IDEA – in my opinion the most productive IDE for Java – comes with bunch of features helpin ...

  7. AI单挑Dota 2世界冠军:被电脑虐哭……

    OpenAI的机器人刚刚在 Dota2 1v1 比赛中战胜了人类顶级职业玩家 Denti.以建设安全的通用人工智能为己任的 OpenAI,通过“Self-Play”的方式,从零开始训练出了这个机器人. ...

  8. px 和 em 的区别

    相同点:px和em都是长度单位: 异同点:px的值是固定的,指定是多少就是多少,计算比较容易.em得值不是固定的,并且em会继承父级元素的字体大小.浏览器的默认字体高都是16px.所以未经调整的浏览器 ...

  9. Java反射机制的使用(全)

    转载请注明原文地址:http://www.cnblogs.com/ygj0930/p/6566957.html  一:反射是什么 JAVA反射机制是在运行状态中,对于任意一个类,都能够知道这个类的所有 ...

  10. picasso 在魅族手机无法加载缩略图的bug

    09-03 12:46:30.722 19088-19088/com.tongyan.subway.maintenance W/PerfScheduler: Cann't find the ListV ...