除1,1其他外国x,y不等于

为 x<y 案件 一切y有phi(y)组合

F[x]= phi(i) 2<=i<=x

结果为 2*F[x]+1

Problem A

Send a Table


Input: Standard Input

Output: Standard Output

When participating in programming contests, you sometimes face the following problem: You know how to calcutale the output for the given input values, but your algorithm is way too slow to ever pass the time limit. However hard you try, you just can't discover
the proper break-off conditions that would bring down the number of iterations to within acceptable limits.

Now if the range of input values is not too big, there is a way out of this. Let your PC rattle for half an hour and produce a table of answers for all possible input values, encode this table into a program, submit it to the judge, et voila: Accepted in
0.000 seconds! (Some would argue that this is cheating, but remember: In love and programming contests everything is permitted).

Faced with this problem during one programming contest, Jimmy decided to apply such a 'technique'. But however hard he tried, he wasn't able to squeeze all his pre-calculated values into a program small enough to pass the judge. The situation looked hopeless,
until he discovered the following property regarding the answers: the answers where calculated from two integers, but whenever the two input values had a common factor, the answer could be easily derived from the answer for which the input values were divided
by that factor. To put it in other words:

Say Jimmy had to calculate a function Answer(x, y) where x and y are both integers in the range [1, N].  When he knows Answer(x, y), he can easily derive Answer(k*x, k*y), where k is any integer from it by applying some simple calculations involving Answer(x,
y) and k. For example if N=4, he only needs to know the answers for 11 out of the 16 possible input value combinations: Answer(1, 1), Answer(1, 2), Answer(2, 1), Answer(1, 3), Answer(2, 3), Answer(3, 2), Answer(3, 1), Answer(1, 4), Answer(3, 4), Answer(4,
3) and Answer(4, 1). The other 5 can be derived from them (Answer(2, 2), Answer(3, 3) and Answer(4, 4) from Answer(1, 1), Answer(2, 4) from Answer(1, 2), and Answer(4, 2) from Answer(2, 1)). Note that the function Answer is not symmetric, so Answer(3, 2) can
not be derived from Answer(2, 3).

Now what we want you to do is: for any values of N from 1 upto and including 50000, give the number of function Jimmy has to pre-calculate.

Input

The input file contains at most 600 lines of inputs. Each line contains an integer less than 50001 which indicates the value of N. Input is terminated by a line which contains a zero. This line should not be processed.

Output

For each line of input produce one line of output. This line contains an integer  which indicates how many values Jimmy has to pre-calculate for a certain value of N.

Sample Input                               Output for Sample Input

2

5

0

         

3

19


Problem setter: Little Joey

Special Thanks: Shahriar Manzoor

 

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm> using namespace std; const int maxn=55000; long long int phi[maxn]; void phi_table()
{
phi[1]=1LL;
for(int i=2;i<maxn;i++)
{
if(!phi[i])
{
for(int j=i;j<maxn;j+=i)
{
if(!phi[j]) phi[j]=j;
phi[j]=phi[j]/i*(i-1);
}
}
}
for(int i=3;i<maxn;i++)
{
phi[i]+=phi[i-1];
}
} int n; int main()
{
phi_table();
while(scanf("%d",&n)!=EOF&&n)
{
if(n==1)
{
puts("1"); continue;
}
printf("%lld\n",1+phi[n]*2);
}
return 0;
}

版权声明:本文博客原创文章。博客,未经同意,不得转载。

UVA 10820 Send a Table euler_phi功能的更多相关文章

  1. UVA 10820 - Send a Table 数论 (欧拉函数)

    Send a Table Input: Standard Input Output: Standard Output When participating in programming contest ...

  2. UVa 10820 - Send a Table(欧拉函数)

    链接: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem& ...

  3. UVa 10820 - Send a Table

    题目:找到整数区间[1.n]中全部的互质数对. 分析:数论,筛法,欧拉函数.在筛素数的的同一时候.直接更新每一个数字的欧拉函数. 每一个数字一定会被他前面的每一个素数筛到.而欧拉函数的计算是n*π(1 ...

  4. Uva 10820 Send a Table(欧拉函数)

    对每个n,答案就是(phi[2]+phi[3]+...+phi[n])*2+1,简单的欧拉函数应用. #include<iostream> #include<cstdio> # ...

  5. UVa10820 Send a Table[欧拉函数]

    Send a TableInput: Standard Input Output: Standard Output When participating in programming contests ...

  6. uva 10820 (筛法构造欧拉函数)

    send a table When participating in programming contests, you sometimes face the following problem: Y ...

  7. 【UVA 10820】Send a Table(欧拉函数)

    Description When participating in programming contests, you sometimes face the following problem: Yo ...

  8. UVa 10820 (打表、欧拉函数) Send a Table

    题意: 题目背景略去,将这道题很容易转化为,给出n求,n以内的有序数对(x, y)互素的对数. 分析: 问题还可以继续转化. 根据对称性,我们可以假设x<y,当x=y时,满足条件的只有(1, 1 ...

  9. Uva 10820 交表

    题目链接:https://uva.onlinejudge.org/external/108/10820.pdf 题意: 对于两个整数 x,y,输出一个函数f(x,y),有个选手想交表,但是,表太大,需 ...

随机推荐

  1. 【水】HDU 2099——整除的尾数

    来源:点击打开链接 数据范围小,枚举水过就行了……不过要注意格式! #include <iostream> #include <cstring> #include <io ...

  2. Rationnal Rose2003安装并破解

    1.安装Rational Rose2003时,在需选择安装项的时候,只选择Rational Rose EnterPrise Edition即可,不需选择其他项,之后选择“DeskTop Install ...

  3. QNX---Interrupt vector numbers(原创!!!)

    Interrupt intr Description 0 A clock that runs at the resolution set by ClockPeriod() 1 Keyboard 2 S ...

  4. 计算机内存碎片(中)——外部碎片化(内存 & 文件系统 & 数据库系统通杀)

    本文原创为freas_1990,转载请标明出处:http://blog.csdn.net/freas_1990/article/details/17252221 外部碎片化 当计算机内存被划分成很细碎 ...

  5. python发送post和get请求

    python发送post和get请求 get请求: 使用get方式时,请求数据直接放在url中. 方法一. import urllib import urllib2 url = "http: ...

  6. 理清JavaScript正则表达式

    理清JavaScript正则表达式--下篇 紧接:"理清JavaScript正则表达式--上篇". 正则在String类中的应用 类String支持四种利用正则表达式的方法.分别是 ...

  7. 综述-如何克服HTML5的“性工能”障碍

    http://ask.dcloud.net.cn/docs HTML5自出现以来,几经风雨,虽看似很有前途,但实际使用问题太多,DCloud为此踩了无数坑.但我们从未放弃,我们加入了W3C,发起了 H ...

  8. Q10Ⅱ 双核 - 产品中心 - 海美迪

    海美迪Q系列视频文明书 Q10Ⅱ 双核 - 产品中心 - 海美迪

  9. Redis核心解读:集群管理工具(Redis-sentinel)

    Redis核心解读:集群管理工具(Redis-sentinel) - Redis - TechTarget数据库 Redis核心解读:集群管理工具(Redis-sentinel)

  10. Fedora 问题总结第二季

    该系列主要是记录自己使用fedora发现的问题. 1Linux Error: curses.h: No such file or directory Problem Solution sudo yum ...