PTA 1155 Heap Paths (DFS)
In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
One thing for sure is that all the keys along any path from the root to a leaf in a max/min heap must be in non-increasing/non-decreasing order.
Your job is to check every path in a given complete binary tree, in order to tell if it is a heap or not.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer \(N (1<N≤1,000)\), the number of keys in the tree. Then the next line contains \(N\) distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, first print all the paths from the root to the leaves. Each path occupies a line, with all the numbers separated by a space, and no extra space at the beginning or the end of the line. The paths must be printed in the following order: for each node in the tree, all the paths in its right subtree must be printed before those in its left subtree.
Finally print in a line
Max Heapif it is a max heap, orMin Heapfor a min heap, orNot Heapif it is not a heap at all.
Sample Input 1:
8
98 72 86 60 65 12 23 50
Sample Output 1:
98 86 23
98 86 12
98 72 65
98 72 60 50
Max Heap
Sample Input 2:
8
8 38 25 58 52 82 70 60
Sample Output 2:
8 25 70
8 25 82
8 38 52
8 38 58 60
Min Heap
Sample Input 3:
8
10 28 15 12 34 9 8 56
Sample Output 3:
10 15 8
10 15 9
10 28 34
10 28 12 56
Not Heap
题意
给定一个长度为 \(N\) 的数组,输出从根节点到叶子结点的每一条路径,并且判断是否是堆。
思路
直接 dfs 输出路径。设立两个变量 Max 和 Min 统计父节点比子节点大的个数和父节点比子节点小的个数。如果两者都不为 0,说明不是堆;如果 Max 为 0,说明是小顶堆,如果 Min 为 0,说明是大顶堆。
代码
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e3 + 10;
int arr[maxn];
int n;
int path[11]; // 保存路径
int Max = 0, Min = 0;
void dfs(int step, int id) {
path[step] = arr[id];
if(id * 2 > n) {
for(int i = 1; i < step; ++i) {
cout << path[i] << " ";
}
cout << path[step] << endl;
return;
}
int l = id * 2, r = id * 2 + 1; // 左右儿子结点
if(r <= n) {
if(path[step] < arr[r]) ++Min;
if(path[step] > arr[r]) ++Max;
dfs(step + 1, r);
}
if(l <= n) {
if(path[step] < arr[l]) ++Min;
if(path[step] > arr[l]) ++Max;
dfs(step + 1, l);
}
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n;
for(int i = 1; i <= n; ++i) {
cin >> arr[i];
}
dfs(1, 1);
if(Min == 0) {
cout << "Max Heap" << endl;
} else if(Max == 0) {
cout << "Min Heap" << endl;
} else {
cout << "Not Heap" << endl;
}
return 0;
}
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