A. The Fair Nut and Elevator（暴力）

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

The Fair Nut lives in nn story house. aiai people live on the ii-th floor of the house. Every person uses elevator twice a day: to get from the floor where he/she lives to the ground (first) floor and to get from the first floor to the floor where he/she lives, when he/she comes back home in the evening.

It was decided that elevator, when it is not used, will stay on the xx-th floor, but xx hasn't been chosen yet. When a person needs to get from floor aa to floor bb, elevator follows the simple algorithm:

• Moves from the xx-th floor (initially it stays on the xx-th floor) to the aa-th and takes the passenger.
• Moves from the aa-th floor to the bb-th floor and lets out the passenger (if aa equals bb, elevator just opens and closes the doors, but stillcomes to the floor from the xx-th floor).
• Moves from the bb-th floor back to the xx-th.

The elevator never transposes more than one person and always goes back to the floor xx before transposing a next passenger. The elevator spends one unit of electricity to move between neighboring floors. So moving from the aa-th floor to the bb-th floor requires |a−b||a−b|units of electricity.

Your task is to help Nut to find the minimum number of electricity units, that it would be enough for one day, by choosing an optimal the xx-th floor. Don't forget than elevator initially stays on the xx-th floor.

Input

The first line contains one integer nn (1≤n≤1001≤n≤100) — the number of floors.

The second line contains nn integers a1,a2,…,ana1,a2,…,an (0≤ai≤1000≤ai≤100) — the number of people on each floor.

Output

In a single line, print the answer to the problem — the minimum number of electricity units.

Examples

input

Copy

3
0 2 1

output

Copy

16

input

Copy

2
1 1

output

Copy

4

Note

In the first example, the answer can be achieved by choosing the second floor as the xx-th floor. Each person from the second floor (there are two of them) would spend 44 units of electricity per day (22 to get down and 22 to get up), and one person from the third would spend 88units of electricity per day (44 to get down and 44 to get up). 4⋅2+8⋅1=164⋅2+8⋅1=16.

In the second example, the answer can be achieved by choosing the first floor as the xx-th floor.

题解：暴力枚举上下楼的过程即可

代码：

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>

using namespace std;

int main()
{
	int n;
	cin>>n;
	int a[105];
	for(int t=1;t<=n;t++)
	{
		scanf("%d",&a[t]);
	}
	long long int s;
	long long int minn=0x3f3f3f;
	for(int t=1;t<=n;t++)
	{
	    s=0;
		for(int j=1;j<=n;j++)
		{
		s+=(abs(j-t)+abs(t-1)+abs(j-1))*2*a[j];
		}
		minn=min(minn,s);
	}
	cout<<minn<<endl;
	return 0;
}