Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

解题思路:略

代码:

 /**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *deleteDuplicates(ListNode *head) {
if (!head)
return head; ListNode *p = head; while(p->next) {
if (p->val == p->next->val) {
p->next = p->next->next;
} else {
p = p->next;
}
} return head;
}
};

附录:

C++链表,申请和消除内存

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