区间DP POJ 1141 Brackets Sequence
Brackets Sequence
Description Let us define a regular brackets sequence in the following way:
1. Empty sequence is a regular sequence. For example, all of the following sequences of characters are regular brackets sequences: (), [], (()), ([]), ()[], ()[()] And all of the following character sequences are not: (, [, ), )(, ([)], ([(] Some sequence of characters '(', ')', '[', and ']' is given. You are to find the shortest possible regular brackets sequence, that contains the given character sequence as a subsequence. Here, a string a1 a2 ... an is called a subsequence of the string b1 b2 ... bm, if there exist such indices 1 = i1 < i2 < ... < in = m, that aj = bij for all 1 = j = n. Input The input file contains at most 100 brackets (characters '(', ')', '[' and ']') that are situated on a single line without any other characters among them.
Output Write to the output file a single line that contains some regular brackets sequence that has the minimal possible length and contains the given sequence as a subsequence.
Sample Input ([(] Sample Output ()[()] /*对于DP题目需要记录到底是怎样得到结果的,不一定了可以通过记录信息直接得到,可以选择数组记录其他有用信息,可以写递归来找出最后的答案。*/ |
区间DP POJ 1141 Brackets Sequence的更多相关文章
- POJ 1141 Brackets Sequence(区间DP, DP打印路径)
Description We give the following inductive definition of a “regular brackets” sequence: the empty s ...
- POJ 1141 Brackets Sequence (区间DP)
Description Let us define a regular brackets sequence in the following way: 1. Empty sequence is a r ...
- poj 1141 Brackets Sequence 区间dp,分块记录
Brackets Sequence Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 35049 Accepted: 101 ...
- POJ 1141 Brackets Sequence(括号匹配二)
题目链接:http://poj.org/problem?id=1141 题目大意:给你一串字符串,让你补全括号,要求补得括号最少,并输出补全后的结果. 解题思路: 开始想的是利用相邻子区间,即dp[i ...
- POJ 1141 Brackets Sequence
Brackets Sequence Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 29502 Accepted: 840 ...
- poj 1141 Brackets Sequence (区间dp)
题目链接:http://poj.org/problem?id=1141 题解:求已知子串最短的括号完备的全序列 代码: #include<iostream> #include<cst ...
- poj 1141 Brackets Sequence(区间DP)
题目:http://poj.org/problem?id=1141 转载:http://blog.csdn.net/lijiecsu/article/details/7589877 定义合法的括号序列 ...
- poj 1141 Brackets Sequence ( 区间dp+输出方案 )
http://blog.csdn.net/cc_again/article/details/10169643 http://blog.csdn.net/lijiecsu/article/details ...
- POJ 1141 Brackets Sequence(DP)
题目链接 很早 很早之前就看过的一题,今天终于A了.状态转移,还算好想,输出路径有些麻烦,搞了一个标记数组的,感觉不大对,一直wa,看到别人有写直接输出的..二了,直接输出就过了.. #include ...
随机推荐
- queue_delayed_work和queue_work区别 (转http://blog.csdn.net/dosculler/article/details/7968101)
queue_delayed_work和queue_work 一.参考文献: 1)http://www.linuxidc.com/Linux/2011-08/41655.htm queue_delaye ...
- Nginx部署部分https与部分http【转】
转自 Nginx部署部分https与部分http - na_tion的专栏 - 博客频道 - CSDN.NEThttp://blog.csdn.net/na_tion/article/details/ ...
- MySQL sleep过多解决方法
睡眠连接过多,会对mysql服务器造成什么影响? 严重消耗mysql服务器资源(主要是cpu, 内存),并可能导致mysql崩溃. 造成睡眠连接过多的原因? 1. 使用了太多持久连接(个人觉得,在高并 ...
- 011 CountDownLatch,CyclicBarrier和Semaphore
CountDownLatch(闭锁,有译倒计数,锁寄存): public class CountDownLatchTest { /*** 比如有一个任务A,它要等待其他4个任务执行完毕之后才能执行,此 ...
- c++动态规划dp算法题
问题1:找硬币,换钱的方法 输入: penny数组代表所有货币的面值,正数不重复 aim小于等于1000,代表要找的钱 输出:换钱的方法总数 解法1:经典dp,空间复杂度O(n*aim) class ...
- MySQL三种备份
一)备份分类 1 2 3 4 5 6 7 8 9 10 11 12 冷备:cold backup数据必须下线后备份 温备:warm backup全局施加共享锁,只能读,不能写 热备:hot backu ...
- C语言花括号
由于C语言本身就是函数式语言,说白了,C程序就是由函数构成的! 所以花括号肯定是用在函数之中,包括函数中的各种流程控制语句中. 实际上,C程序中花括号{}的作用:就是把多个单条语句用花括号{}括起来组 ...
- java经典面试题大全
基本概念 操作系统中 heap 和 stack 的区别 什么是基于注解的切面实现 什么是 对象/关系 映射集成模块 什么是 Java 的反射机制 什么是 ACID BS与CS的联系与区别 Cookie ...
- admin组件详解
admin组件详解 先根据admin组件启动流程复习下django项目启动至请求过来发生的事 1将admin组件注册进app 2django项目启动 3在运行到定制的admin时执行其下面的apps文 ...
- HDU 2053 Switch Game(开灯问题,完全平方数)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2053 题目大意:灯开始是关着的,有n盏灯,i从1数到n每当灯的序号是i的倍数的时候就对灯进行一次操作( ...