CF914A Perfect Squares
题意翻译
给定一组有n个整数的数组a1,a2,…,an.找出这组数中的最大非完全平方数。 完全平方数是指有这样的一个数x,存在整数y,使得x=y^2y2 .
输入格式
第一行输入一个单独的整数n(1<=n<=1000 ),n为该组数的数量。 接下来有n个整数,a1,a2,an(-10^6<=a<=10^6) 数据保证至少存在一个整数是非完全平方数。
题目描述
Given an array a_{1},a_{2},...,a_{n}a1,a2,...,an of nn integers, find the largest number in the array that is not a perfect square.
A number xx is said to be a perfect square if there exists an integer yy such that x=y^{2}x=y2 .
输入输出格式
输入格式:
The first line contains a single integer nn ( 1<=n<=10001<=n<=1000 ) — the number of elements in the array.
The second line contains nn integers a_{1},a_{2},...,a_{n}a1,a2,...,an ( -10^{6}<=a_{i}<=10^{6}−106<=ai<=106 ) — the elements of the array.
It is guaranteed that at least one element of the array is not a perfect square.
输出格式:
Print the largest number in the array which is not a perfect square. It is guaranteed that an answer always exists.
输入输出样例
说明
In the first sample case, 44 is a perfect square, so the largest number in the array that is not a perfect square is 22 .

#include<cmath>
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#define MAXN 1001
using namespace std;
int n;
int num[MAXN];
int main(){
scanf("%d",&n);
for(int i=;i<=n;i++)
scanf("%d",&num[i]);
sort(num+,num++n);
for(int i=n;i>=;i--){
int k=sqrt(num[i]);
if(k*k!=num[i]){
cout<<num[i];
return ;
}
}
}
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