hdoj--2522--A simple problem(数学模拟)

A simple problem

Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 3866    Accepted Submission(s): 1444

Problem Description

Zty很痴迷数学问题.。一天，yifenfei出了个数学题想难倒他，让他回答1 / n。但Zty却回答不了^_^. 请大家编程帮助他.

 

Input

第一行整数T，表示测试组数。后面T行，每行一个整数 n (1<=|n|<=10^5).

 

Output

输出1/n. (是循环小数的,只输出第一个循环节).

 

Sample Input

4
2
3
7
168

 

Sample Output

0.5
0.3
0.142857
0.005952380

 

Author

yifenfei

 

Source

HDU 2008-10 Programming Contest

 

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/*其实这一道题跟一般的数学除法很像，只是真正的小数除法都是在小数点后边，
但是那样在c语言中是行不通的，所以每一步乘以10来计算，vis标记是否出现过*/
#include<stdio.h>
#include<string.h>
#define 100000+100
int vis[MAX];
int main()
{
	int yu,t,n;
	scanf("%d",&t);
	while(t--)
	{
		scanf("%d",&n);
		if(n==1)
		{
			printf("1\n");
			continue;
		}
		if(n<0)
		{
			printf("-");
			n=-n;
		}
		printf("0.");
		memset(vis,0,sizeof(vis));
		yu=1,vis[1]=1;
		while(yu)
		{
			yu*=10;
			printf("%d",yu/10);
			yu%=10;
			if(vis[yu])
			break;
			vis[yu]=1;
		}
		printf("\n");
	}
	return 0;
}