HDU1864 最大报销额 01背包

非常裸的01背包，水题。注意控制精度

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <cstdlib>
const int INF = 1e6;
using namespace std;
int dp[4*INF],cost[5],w[31];
int max(int x,int y)
{
    if(x > y)
        return x;
        else
    return y;
}
int min(int x,int y)
{
    if(x > y)
        return y;
        else
    return x;
}
int main()
{
    double z; int n,zong,m;
    char mm;
    while(~scanf("%lf%d",&z,&n))
    {
        if(n==0) break;
        zong = z * 100; int l = 1;
        memset(w,0,sizeof(w));
        for(int i = 1;i<=n;i++)
        {
            scanf("%d",&m);
            int sum = 0;
            memset(cost,0,sizeof(cost));
            int flag = 1;
            for(int j = 0;j<m;j++)
            {
                scanf(" %c:%lf",&mm,&z);
                if(mm=='A') cost[1] += z * 100;
                else if(mm=='B') cost[2] += z * 100;
                else if(mm=='C') cost[3] += z * 100;
                else  flag = 0;
            }
            if(!flag)
                continue;
            if(cost[1]<=60000 &&cost[2]<=60000 &&cost[3]<=60000)
                sum += cost[1]+cost[2]+cost[3];
            if(sum<=10000000)
            {
                w[l++] = sum;
               // cout<<"w[l]="<<w[l-1]<<endl;
            }
        }
        memset(dp,0,sizeof(dp));
        for(int i = 1;i<=l;i++)
        {
            for(int j = zong;j>=w[i];j--)
            {
                if(dp[j]<dp[j-w[i]]+w[i])
                    dp[j] = dp[j-w[i]]+w[i];
            }
        }
        printf("%.2lf\n",dp[zong]*1.0/100);
    }
    return 0;
}