Codeforces 2A ：winner

A. Winner

time limit per test

1 second

memory limit per test

64 megabytes

input

standard input

output

standard output

The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number
of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name
score", where name is a player's name, and score is
the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to m)
at the end of the game, than wins the one of them who scored at least m points
first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points.

Input

The first line contains an integer number n (1  ≤  n  ≤  1000), n is
the number of rounds played. Then follow n lines, containing the information about the rounds in "name
score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is
an integer number between -1000 and 1000, inclusive.

Output

Print the name of the winner.

Sample test(s)

input

3
mike 3
andrew 5
mike 2

output

andrew

input

3
andrew 3
andrew 2
mike 5

output

andrew

做Codeforces上的题还很少，但只从这道题来说，这题无论从题意还是各个方面都足够有趣。一共有n轮比赛，接下来的每行代表这一轮比赛中，这个人得到的分数，分数可正可负。问最先到达最大分值的人是谁。

大一的时候做这个居然用的是数组，现在用map果然方便太多了，但还是因为一开始没注意有可能是负数导致，判断的时候出现了问题。

一共判断的时候有两轮，第一轮判断这个人的结果是不是最大值，如果是最大值，就要看它是不是第一个到达的，也即第二轮的成绩是不是大于或是等于最大值，如果满足条件，赶紧输出结果，就行了。最近做题被虐的都没人样了。。。

代码：

#include <iostream>
#include <map>
#include <cstring>
#include <string>
#include <algorithm>
using namespace std;

//一开始没有考虑到负数的情况，出现了错误。出现负数的话，分数就会下降，之前的最大值就不会对。

map<string,int> round;
map<string,int> round2;

string name[1005];
int score[1005];

int main()
{
	int count,i;
	cin>>count;

	round.clear();

	int max = -1000005;
	string max_name;

	for(i=1;i<=count;i++)
	{
		cin>>name[i]>>score[i];

		round[name[i]] += score[i];
	}

	for(i=1;i<=count;i++)
	{
		if(round[name[i]]>max)
		{
			max=round[name[i]];
		}
	}

	for(i=1;i<=count;i++)
	{
		if(round[name[i]] == max)
		{
			round2[name[i]] += score[i];

			if(round2[name[i]]>=max)//最先到达
			{
				cout<<name[i]<<endl;
				return 0;
			}
		}
	}

	return 0;
}

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