codeforces 622B B. The Time

B. The Time

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.

Note that you should find only the time after a minutes, see the examples to clarify the problem statement.

You can read more about 24-hour format here https://en.wikipedia.org/wiki/24-hour_clock.

Input

The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).

The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.

Output

The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).

See the examples to check the input/output format.

Examples

input

23:59
10

output

00:09

input

20:20
121

output

22:21

input

10:10
0

output

10:10

题意：问从起点时间经过所给的时间，终点时间是多少；

思路：将时间都转换成分钟；

ＡＣ代码：

#include <bits/stdc++.h>
using namespace std;
char str[8];
int a;
int main()
{
    scanf("%s",str);
    scanf("%d",&a);
    int x1,x2;
    x1=(str[0]-'0')*10+(str[1]-'0');
    x2=(str[3]-'0')*10+(str[4]-'0');
    //cout<<x1<<":"<<x2<<"\n";
    x2+=a;
    x1+=x2/60;
    x2%=60;
    x1%=24;
    if(x1<10)printf("0%d:",x1);
    else printf("%d:",x1);
    if(x2<10)printf("0%d\n",x2);
    else printf("%d\n",x2);
    return 0;
}