Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.

For example, given the range [5, 7], you should return 4.

解题思路:

本题有很多思路,最简单的方法:

result就是m和n二进制前面相同的部分!!!

JAVA实现如下:

    public int rangeBitwiseAnd(int m, int n) {
int count=0;
while(m!=n){
n>>>=1;
m>>>=1;
count++;
}
return m<<count;
}

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