#include<iostream>
#include<cmath>
using namespace std;
int main(){
 int n;
 cin>>n;
 while(n--){
  int t;
  cin>>t;
  int points=0;
  while(t--){
   int a,b;
   cin>>a>>b;
   if((a>10&&a<50)&&(b>10&&b<50)){
    if(pow(a-30,2)+pow(b-30,2)<400)
    points+=1;
   }
   if((a>90&&a<110)&&b>20&&b<40) {
    if(pow(a-100,2)+pow(b-30,2)<100) points+=2;
   }
   if((a>165&&a<175)&&b>25&&b<35){
    if(pow(a-170,2)+pow(b-30,2)<25) points+=3;
   }
  }
  cout<<points<<endl;
 }
 return 0;
}

1795. Table tennis的更多相关文章

  1. PAT 1026. Table Tennis

    A table tennis club has N tables available to the public.  The tables are numbered from 1 to N.  For ...

  2. 1026. Table Tennis (30)

    题目如下: A table tennis club has N tables available to the public. The tables are numbered from 1 to N. ...

  3. PAT A1026 Table Tennis (30 分)——队列

    A table tennis club has N tables available to the public. The tables are numbered from 1 to N. For a ...

  4. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) C. Table Tennis Game 2 水题

    C. Table Tennis Game 2 题目连接: http://codeforces.com/contest/765/problem/C Description Misha and Vanya ...

  5. PAT 1026 Table Tennis[比较难]

    1026 Table Tennis (30)(30 分) A table tennis club has N tables available to the public. The tables ar ...

  6. 443 B. Table Tennis

    http://codeforces.com/contest/879/problem/B n people are standing in a line to play table tennis. At ...

  7. Table Tennis Game 2(找规律)

    Description Misha and Vanya have played several table tennis sets. Each set consists of several serv ...

  8. PAT甲级1026. Table Tennis

    PAT甲级1026. Table Tennis 题意: 乒乓球俱乐部有N张桌子供公众使用.表的编号从1到N.对于任何一对玩家,如果有一些表在到达时打开,它们将被分配给具有最小数字的可用表.如果所有的表 ...

  9. PAT 甲级 1026 Table Tennis(模拟)

    1026. Table Tennis (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A table ...

随机推荐

  1. svn 提交失败

    刚刚使用SVN 提交代码时提示失败. svn: Commit failed (details follow):svn: Can't open file '/home/svn/project/db/tx ...

  2. nginx+tomcat+memcached-session-manager组成简单的负载均衡和集群

    1.搭建环境 192.168.29.128(luxh-01.com) 安装nginx,参考 http://www.cnblogs.com/luxh/p/4067038.html 192.168.29. ...

  3. 70. Implement strStr() 与 KMP算法

    Implement strStr() Implement strStr(). Returns a pointer to the first occurrence of needle in haysta ...

  4. QQ粘性布局

    *:first-child { margin-top: 0 !important; } body > *:last-child { margin-bottom: 0 !important; } ...

  5. transition实现自定义tips淡入淡出效果

    transition实现动画的时候,只能实现指定属性的渐变,元素显隐要通过opacity来实现: 做了一个小的demo: <!doctype html> <html> < ...

  6. java泛型中的super和extend

    List<? extend Fruit> list=new ArrayList<>();  解释为:集合中元素是继承自Fruit,究竟是何种类型,编译器也无法判定. 如果要从集 ...

  7. projecteuler 10001st prime (求出第10001个质数)

    By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13. ...

  8. JAVA的Random类[转]

    在实际的项目开发过程中,经常需要产生一些随机数值,例如网站登录中的校验数字等,或者需要以一定的几率实现某种效果,例如游戏程序中的物品掉落等. 在Java API中,在java.util包中专门提供了一 ...

  9. Jsoncpp的使用

    JSON(JavaScript Object Notation) 是一种轻量级的数据交换格式. 易于人阅读和编写.同时也易于机器解析和生成. 它基于JavaScript Programming Lan ...

  10. CIDR-Address介绍

    CIDR是一种用二进制表示法来代替十进制表示法的新方法. IP地址有“类”的概念,/8掩码是A类,/16掩码是B类,/24掩码是C类等等.但是/12,/18,/25呢?这就是无类的概念了,CIDR的作 ...