PAT 1026. Table Tennis
A table tennis club has N tables available to the public. The tables are numbered from 1 to N. For any pair of players, if there are some tables open when they arrive, they will be assigned to the available table with the smallest number. If all the tables are occupied, they will have to wait in a queue. It is assumed that every pair of players can play for at most 2 hours.
Your job is to count for everyone in queue their waiting time, and for each table the number of players it has served for the day.
One thing that makes this procedure a bit complicated is that the club reserves some tables for their VIP members. When a VIP table is open, the first VIP pair in the queue will have the priviledge to take it. However, if there is no VIP in the queue, the next pair of players can take it. On the other hand, if when it is the turn of a VIP pair, yet no VIP table is available, they can be assigned as any ordinary players.
Input Specification:
Each input file contains one test case. For each case, the first line contains an integer N (<=10000) - the total number of pairs of players. Then N lines follow, each contains 2 times and a VIP tag: HH:MM:SS - the arriving time, P - the playing time in minutes of a pair of players, and tag - which is 1 if they hold a VIP card, or 0 if not. It is guaranteed that the arriving time is between 08:00:00 and 21:00:00 while the club is open. It is assumed that no two customers arrives at the same time. Following the players' info, there are 2 positive integers: K (<=100) - the number of tables, and M (< K) - the number of VIP tables. The last line contains M table numbers.
Output Specification:
For each test case, first print the arriving time, serving time and the waiting time for each pair of players in the format shown by the sample. Then print in a line the number of players served by each table. Notice that the output must be listed in chronological order of the serving time. The waiting time must be rounded up to an integer minute(s). If one cannot get a table before the closing time, their information must NOT be printed.
Sample Input:
9
20:52:00 10 0
08:00:00 20 0
08:02:00 30 0
20:51:00 10 0
08:10:00 5 0
08:12:00 10 1
20:50:00 10 0
08:01:30 15 1
20:53:00 10 1
3 1
2
Sample Output:
08:00:00 08:00:00 0
08:01:30 08:01:30 0
08:02:00 08:02:00 0
08:12:00 08:16:30 5
08:10:00 08:20:00 10
20:50:00 20:50:00 0
20:51:00 20:51:00 0
20:52:00 20:52:00 0
3 3 2 此题很遗憾,之拿到23分,但是觉得很有成就感
// 1026pat.cpp : 定义控制台应用程序的入口点。
// #include <fstream>
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <time.h>
#include <math.h>
using namespace std; const int NP=;
const int NT=;
const int INF=0x7fffffff;
const int closeTime=*; struct Player
{
string arrive_time; //arrive time in string format
string serve_time; //serve time in string format
int serve_second; //serve time int seconds of integer
int arrive_second; //arrive time in seconds of integer
int play_time; //play time in minutes
int play_second; //play time in seconds
int wait_time; //wait time
bool VIP; //Vip
bool operator<(const Player& rhs) const
{
return arrive_time<rhs.arrive_time;
}
}; struct Table
{
int serve_nums;
int next_available_time;
bool VIPT;
}; vector<Player> players;
vector<Player> RecordPlayers;
vector<Table> tables;
vector<int> vipTables; int n,k,m;; int find_available_table(int arrive_time)
{
for(int i=;i<=k;++i)
{
if(tables[i].next_available_time<=arrive_time)
return i;
}
return -;
} int find_earlist_table()
{
int min=INF;
int table;
for(int i=;i<=k;++i)
{
if(tables[i].next_available_time<min)
{
min=tables[i].next_available_time;
table=i;
}
}
return table;
} bool isVipTable(int x)
{
for(int i=;i<m;++i)
{
if(vipTables[i]==x)
return true;
}
return false;
} bool isVipPlayer(const Player& player)
{
if(player.VIP)
return true;
else
return false;
} int findVip_available_table(int arrive_second)
{
for(int i=;i<m;++i)
{
if(tables[vipTables[i]].next_available_time<=arrive_second)
return vipTables[i];
}
return -;
} int findVip_player_Inqueue(int cur,int available_time)
{
for(int i=cur+;i<n;++i)
{
if(players[i].VIP&&players[i].arrive_second<=available_time)
return i;
}
return -;
} class T:public binary_function<Player,Player,bool>
{
public:
bool operator()(const Player& lhs,const Player& rhs) const
{
return lhs.serve_time<rhs.serve_time;
}
};
int _tmain(int argc, _TCHAR* argv[])
{while(cin>>n)
{
//clear the buffer
players.clear();
tables.clear();
vipTables.clear();
Player player;
int h,min,s;
for(int i=;i<=n;++i)
{
cin>>player.arrive_time>>player.play_time>>player.VIP;
sscanf(player.arrive_time.c_str(),"%d:%d:%d",&h,&min,&s);
player.arrive_second=*h+*min+s;
if(player.play_time>)
player.play_time=;
player.play_second=*player.play_time;
player.wait_time=;
players.push_back(player);
}
sort(players.begin(),players.end());
cin>>k>>m;
Table table;
table.VIPT=;
tables.push_back(table);
for(int i=;i<=k;++i)
{
table.next_available_time=*;
table.VIPT=;
table.serve_nums=;
tables.push_back(table);
}
int vip;
for(int i=;i<=m;++i)
{
cin>>vip;
vipTables.push_back(vip);
tables[vip].VIPT=;
} //deal with the core process
int tnum;
bool nvip=false;
for(int i=;i<n;++i)
{
if(players[i].VIP)//vip player case
{
tnum=findVip_available_table(players[i].arrive_second);
if(tnum>)//vip player vip table
{
if(tables[tnum].next_available_time<closeTime)
{
++tables[tnum].serve_nums;
players[i].serve_second=players[i].arrive_second;
tables[tnum].next_available_time=players[i].arrive_second+players[i].play_second;
RecordPlayers.push_back(players[i]);
}
else
nvip=true;
}//vip player vip table
else
{
tnum=find_available_table(players[i].arrive_second);
if(tnum>)
{
if(tables[tnum].next_available_time<closeTime)
{
++tables[tnum].serve_nums;
players[i].serve_second=players[i].arrive_second;
tables[tnum].next_available_time=players[i].arrive_second+players[i].play_second;
RecordPlayers.push_back(players[i]);
}
else
{
if(nvip)
break;
} }//vip player common table
else
{
tnum=find_earlist_table();
if(tables[tnum].next_available_time<closeTime)
{
++tables[tnum].serve_nums;
players[i].serve_second=tables[tnum].next_available_time;
players[i].wait_time=tables[tnum].next_available_time-players[i].arrive_second;
tables[tnum].next_available_time=tables[tnum].next_available_time+players[i].play_second;
RecordPlayers.push_back(players[i]);
}
else
break;
}//vip player have to wait
}
}//vip player case
else //common player case
{
tnum=find_available_table(players[i].arrive_second);
if(tnum>)
{
if(tables[tnum].next_available_time<closeTime)
{
++tables[tnum].serve_nums;
players[i].serve_second=players[i].arrive_second;
tables[tnum].next_available_time=players[i].arrive_second+players[i].play_second;
RecordPlayers.push_back(players[i]);
}
else
break;
}//available table
else
{
tnum=find_earlist_table();
if(tables[tnum].next_available_time<closeTime)
{
int vp=findVip_player_Inqueue(i,tables[tnum].next_available_time);
if(vp>-)
{
++tables[tnum].serve_nums;
players[vp].serve_second=tables[tnum].next_available_time;
players[vp].wait_time=tables[tnum].next_available_time-players[vp].arrive_second;
tables[tnum].next_available_time+=players[vp].play_second;
RecordPlayers.push_back(players[vp]);
players.erase(players.begin()+vp);
--i;
--n;
continue;
}
else
{
++tables[tnum].serve_nums;
players[i].serve_second=tables[tnum].next_available_time;
players[i].wait_time=tables[tnum].next_available_time-players[i].arrive_second;
tables[tnum].next_available_time+=players[i].play_second;
RecordPlayers.push_back(players[i]);
}
}
else
break;
}//common player have to wait
}//common player case
}//the core calculation process //output the result
for(vector<Player>::iterator iter=RecordPlayers.begin();iter!=RecordPlayers.end();++iter)
{
int hr,me,sd;
hr=iter->serve_second/;
me=(iter->serve_second/)%;
sd=iter->serve_second%;
char tmp[];
tm hms;
hms.tm_hour=hr;
hms.tm_min=me;
hms.tm_sec=sd;
strftime(tmp,sizeof(tmp),"%H:%M:%S",&hms);
iter->serve_time=tmp;
iter->wait_time=(1.0*iter->wait_time/60.0+0.5);
}
sort(RecordPlayers.begin(),RecordPlayers.end(),T());
for(vector<Player>::iterator iter=RecordPlayers.begin();iter!=RecordPlayers.end();++iter)
{
cout<<iter->arrive_time<<" "<<iter->serve_time<<" "<<iter->wait_time<<endl;
}
bool flag=true;
for(vector<Table>::iterator iter=tables.begin()+;iter!=tables.end();++iter)
{
if(flag)
{
cout<<iter->serve_nums;
flag=false;
}
else
cout<<" "<<iter->serve_nums;
}
cout<<endl;
}
return ;
}
PAT 1026. Table Tennis的更多相关文章
- PAT 1026 Table Tennis[比较难]
1026 Table Tennis (30)(30 分) A table tennis club has N tables available to the public. The tables ar ...
- PAT 1026 Table Tennis (30)
A table tennis club has N tables available to the public. The tables are numbered from 1 to N. For a ...
- PAT甲级1026. Table Tennis
PAT甲级1026. Table Tennis 题意: 乒乓球俱乐部有N张桌子供公众使用.表的编号从1到N.对于任何一对玩家,如果有一些表在到达时打开,它们将被分配给具有最小数字的可用表.如果所有的表 ...
- PAT 甲级 1026 Table Tennis(模拟)
1026. Table Tennis (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A table ...
- PAT 甲级 1026 Table Tennis (30 分)(坑点很多,逻辑较复杂,做了1天)
1026 Table Tennis (30 分) A table tennis club has N tables available to the public. The tables are ...
- 1026. Table Tennis (30)
题目如下: A table tennis club has N tables available to the public. The tables are numbered from 1 to N. ...
- PAT A1026 Table Tennis (30 分)——队列
A table tennis club has N tables available to the public. The tables are numbered from 1 to N. For a ...
- 1026 Table Tennis (30)(30 分)
A table tennis club has N tables available to the public. The tables are numbered from 1 to N. For a ...
- 1026 Table Tennis (30分)
A table tennis club has N tables available to the public. The tables are numbered from 1 to N. For a ...
随机推荐
- sitecustomize.py 用法
1.在python安装目录下的lib下的site-packages 目录中,新建文件sitecustomize.py.这是个特殊的文件,在python启动时会自动执行其中的语句.在sitecustom ...
- WARNING L15: MULTIPLE CALL TO SEGMENT
原网页:http://www.cnblogs.com/CuriosityWzk/archive/2011/12/25/2301090.html WARNING L15: MULTIPLE CALL T ...
- cocos2d-x笔记5: 通过jni实现C++调用Java
Cocos2d-x的跨平台性很强大,但是偶尔也需要平台的原生API结合. C++在Win32平台下简单的很,C++可以直接用MFC或者调用Win32API. Ios在XCode下直接就能C++和OC混 ...
- Docker入门
-----------------------------------------Docker入门教程(一)介绍Docker入门教程(二)命令Docker入门教程(三)DockerFileDocker ...
- 集合工具类 - CollectionUtil.java
集合工具类,提供数组转LIST.数组转SET.合并集合.计算笛卡儿积等方法. 源码如下:(点击下载 - CollectionUtil.java.ArrayUtil.java.commons-lang ...
- c/c++动态分配内存和malloc的使用
c/c++动态分配内存 为什么需要动态分配内存 ---很好的解决的了传统数组的4个缺陷 动态内存分配举例 ---动态数组的构造 使用动态数组的优点: 1. 动态数组长度不需要事先给定: 2. ...
- 在Eclipse中安装ADT
启动 Eclipse,然后选择 Help > Software Updates….在出现的对话框中,单击 Available Software 选项卡. 单击 Add Site 在 Add Si ...
- js node
http://blogs.msdn.com/b/scott_hanselman/archive/2011/11/29/window-iis-node-js.aspx http://www.16kan. ...
- 深入浅出Z-Stack 2006 OSAL多任务资源分配机制
转自深入浅出Z-Stack 2006 OSAL多任务资源分配机制 一.概述 OSAL (Operating System Abstraction Layer),翻译为"操作系统抽象层&quo ...
- 前端性能优化(三)——传统 JavaScript 优化的误区
注:本文是纯技术探讨文,无图无笑点,希望您喜欢 一.前言 软件行业极其缺乏前端人才这是圈内的共识了,某种程度上讲,同等水平前端的工资都要比后端高上不少,而圈内的另一项共识则是--网页是公司的脸面! 几 ...