MySQL学习笔记：创建整年日期

　　见识到另外一种创意，惊讶！

　　1.创建小数据表 0-9

# 创建小数据表 0-9
DROP TABLE IF EXISTS aa_numbers_small;
CREATE TABLE aa_numbers_small(
    number INT);
INSERT INTO aa_numbers_small VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9);
SELECT * FROM aa_numbers_small;

　　2.创建大数据表 0-10000

# 创建大数据表 0-10000
DROP TABLE IF EXISTS aa_numbers;
CREATE TABLE aa_numbers(number BIGINT);
INSERT INTO aa_numbers
SELECT thousand.number*1000+hundred.number*100+ten.number*10+ones.number
FROM aa_numbers_small thousand, aa_numbers_small hundred, aa_numbers_small ten, aa_numbers_small ones
LIMIT 1000000;
SELECT * FROM aa_numbers;

　　3.创建时间维表

# 创建时间维表
DROP TABLE IF EXISTS aa_date;
CREATE TABLE aa_date(
    date_id          BIGINT PRIMARY KEY,
    DATE             DATE NOT NULL,
    DAY              CHAR(10),
    day_of_week      INT,
    day_of_month     INT,
    day_of_year      INT,
    previous_day     DATE NOT NULL DEFAULT '0000-00-00',
    next_day         DATE NOT NULL DEFAULT '0000-00-00',
    weekend          CHAR(10) NOT NULL DEFAULT "Weekday",
    week_of_year     CHAR(2),
    MONTH            CHAR(10),
    month_of_year    CHAR(2),
    quarter_of_year INT,
    YEAR             INT,
    UNIQUE KEY `date` (`date`));

SELECT * FROM aa_date;

　　4.填充数据

# 填充数据
INSERT INTO aa_date(date_id, DATE)
SELECT number, DATE_ADD('2018-01-01', INTERVAL number DAY)
FROM aa_numbers
WHERE DATE_ADD('2018-01-01', INTERVAL number DAY) BETWEEN '2018-01-01' AND '2018-12-31'
ORDER BY number;

　　5.根据日期update其他列数据

# 根据日期update其他列数据
UPDATE aa_date SET
DAY             = DATE_FORMAT( DATE, "%W" ),
day_of_week     = DAYOFWEEK(DATE),
day_of_month    = DATE_FORMAT( DATE, "%d" ),
day_of_year     = DATE_FORMAT( DATE, "%j" ),
previous_day    = DATE_ADD(DATE, INTERVAL -1 DAY),
next_day        = DATE_ADD(DATE, INTERVAL 1 DAY),
weekend         = IF( DATE_FORMAT( DATE, "%W" ) IN ('Saturday','Sunday'), 'Weekend', 'Weekday'),
week_of_year    = DATE_FORMAT( DATE, "%V" ),
MONTH           = DATE_FORMAT( DATE, "%M"),
month_of_year   = DATE_FORMAT( DATE, "%m"),
quarter_of_year = QUARTER(DATE),
YEAR            = DATE_FORMAT( DATE, "%Y" );

　　6.日期函数测试

# 测试
SELECT DATE_FORMAT('2018-05-29', '%W'); # Tuesday
SELECT DAYOFWEEK('2018-05-29'); # 3
SELECT DATE_FORMAT('2018-05-29', '%d'); # 29
SELECT DATE_FORMAT('2018-05-29', '%j'); # 149
SELECT DATE_ADD('2018-05-29', INTERVAL -1 DAY); # 2018-05-28
SELECT DATE_SUB('2018-05-29', INTERVAL 1 DAY); # 2018-05-28
SELECT DATE_ADD('2018-05-29', INTERVAL 1 DAY); # 2018-05-30
SELECT IF(DATE_FORMAT('2018-05-26', '%W') IN ('Saturday','Sunday'), 'Weekend', 'Weekday'); # Weekend
SELECT DATE_FORMAT('2018-05-29', '%V'); # 21
SELECT DATE_FORMAT('2018-05-29', '%M'); # May
SELECT DATE_FORMAT('2018-05-29', '%m'); # 05
SELECT QUARTER('2018-05-29') # 2
SELECT DATE_FORMAT('2018-05-29', '%Y');# 2018

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END 2018-05-29 14:34:57