C# STUDY
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace WindowsFormsApplication3
{
public partial class Form1 : Form
{
public delegate void TimerHandler();
public event TimerHandler m_TimerEvent;
public int m_offset;
private System.Timers.Timer m_timer;
private List<System.Drawing.Point> m_orinLocation;
private List<System.Windows.Forms.Button> m_Buttons;
public Form1()
{
InitializeComponent();
m_timer = new System.Timers.Timer(50);
m_timer.Elapsed += new System.Timers.ElapsedEventHandler(theout);
m_timer.Enabled = true;
m_orinLocation = new List<System.Drawing.Point>();
m_Buttons = new List<System.Windows.Forms.Button>();
m_orinLocation.Add(button1.Location);
m_orinLocation.Add(button2.Location);
m_orinLocation.Add(button3.Location);
m_orinLocation.Add(button4.Location);
m_orinLocation.Add(button5.Location);
m_orinLocation.Add(button6.Location);
m_orinLocation.Add(button7.Location);
m_orinLocation.Add(button8.Location);
m_orinLocation.Add(button9.Location);
m_Buttons.Add(button1);
m_Buttons.Add(button2);
m_Buttons.Add(button3);
m_Buttons.Add(button4);
m_Buttons.Add(button5);
m_Buttons.Add(button6);
m_Buttons.Add(button7);
m_Buttons.Add(button8);
m_Buttons.Add(button9);
m_offset = 0;
m_TimerEvent += process;
}
public void process()
{
m_timer.Enabled = false;
int itemHeight = this.button1.Height;
System.Console.WriteLine("Process m_offset{0}, mod{1}", m_offset, m_offset % itemHeight);
m_offset += itemHeight / 2;
if (m_offset >= itemHeight)
{
m_offset = 0;
for (int i = 0; i < 9; ++i)
{
m_Buttons[i].Location = new System.Drawing.Point(m_orinLocation[i].X, m_orinLocation[i].Y);
}
}
else
{
for (int i = 0; i < 9; ++i)
{
m_Buttons[i].Location = new System.Drawing.Point(m_orinLocation[i].X, m_orinLocation[i].Y - m_offset);
}
}
m_timer.Enabled = true;
}
public void theout(object source, System.Timers.ElapsedEventArgs e)
{
try
{
if (m_TimerEvent != null)
this.Invoke(m_TimerEvent);
}
catch(System.Exception err)
{
Console.WriteLine("{0}",err.Message);
}
}
private void button10_Click(object sender, EventArgs e)
{
}
protected override void OnClosing(CancelEventArgs e)
{
m_timer.Stop();
m_timer.Close();
m_TimerEvent = null;
}
protected override void OnPaint(PaintEventArgs e)
{
base.OnPaint(e);
}
}
}
C# STUDY的更多相关文章
- Improve Your Study Habits
1.Plan your time carefully. Make a list of your weekly tasks.Then make a schedule or chart of your t ...
- RSA Study
These days I study the RSA Algorithm. It is a little complex, but not very. Also, my study has not f ...
- Machine Learning Algorithms Study Notes(3)--Learning Theory
Machine Learning Algorithms Study Notes 高雪松 @雪松Cedro Microsoft MVP 本系列文章是Andrew Ng 在斯坦福的机器学习课程 CS 22 ...
- Machine Learning Algorithms Study Notes(2)--Supervised Learning
Machine Learning Algorithms Study Notes 高雪松 @雪松Cedro Microsoft MVP 本系列文章是Andrew Ng 在斯坦福的机器学习课程 CS 22 ...
- Machine Learning Algorithms Study Notes(1)--Introduction
Machine Learning Algorithms Study Notes 高雪松 @雪松Cedro Microsoft MVP 目 录 1 Introduction 1 1.1 ...
- jar tvf study.war jar命令查看war/jar包的内容
jar tvf study.war 0 Thu Oct 20 14:01:18 CST 2016 META-INF/ 137 Thu Oct 20 14:01:16 CST 2016 META-INF ...
- Mongo DB Study: first face with mongo DB
Mongo DB Study: first face with mongo DB 1. study methods: 1. Translate: I am the mongo DB organiz ...
- A Study of WebRTC Security
转自:http://webrtc-security.github.io/ A Study of WebRTC Security Abstract Web Real-Time Communication ...
- study topics
永远不变的东西,原理 study roadmap: 1.user space: tizen power manager => suspend/resume or runtime? android ...
- 读书笔记2013第10本:《学得少却考得好Learn More Study Less》
<学得少却考得好Learn More Study Less>这本书最早是从褪墨网站上看到的,crowncheng翻译了全文.这本书介绍了不少学习方法,非常适合在校的学生,原文的作者Scot ...
随机推荐
- leetcode 97 Interleaving String ----- java
Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2. For example,Given:s1 = ...
- HDU 5957 Query on a graph
HDU 5957 Query on a graph 2016ACM/ICPC亚洲区沈阳站 题意 \(N(N \le 10^5)\)个点,\(N\)条边的连通图. 有\(M \le 10^5\)操作: ...
- codeForce-19D Points (点更新+离散化)
题目大意:在二维坐标系的x正半轴,y正半轴和第一象限内,有三种操作: 1.add x,y (添加点<x,y>): 2.remove x,y(移除点<x,y>): 3.find ...
- kuangbin_ShortPath S (POJ 3169)
被cow类题目弄得有些炸裂 想了好久好久写了120多行 依然长跪不起发现计算约束条件的时候还是好多麻烦的地方过不去 然后看了看kuangbin的blog 都是泪啊 差分约束的方式做起来只要70多行啊炒 ...
- android开源项目---tool篇
本文转载于:http://blog.csdn.net/likebamboo/article/details/19080801 主要包括那些不错的开发库,包括依赖注入框架.图片缓存.网络相关.数据库OR ...
- Windows下IntelliJ IDEA中运行Spark Standalone
ZHUAN http://www.cnblogs.com/one--way/archive/2016/08/29/5818989.html http://www.cnblogs.com/one--wa ...
- CUDA学习笔记(一)【转】
CUDA编程中,习惯称CPU为Host,GPU为Device.编程中最开始接触的东西恐怕是并行架构,诸如Grid.Block的区别会让人一头雾水,我所看的书上所讲述的内容比较抽象,对这些概念的内容没有 ...
- kmeans算法
# coding:utf-8 import numpy as np import matplotlib.pyplot as plt def dis(x, y): #计算距离 return np.sum ...
- Postfix性能测试(PHP版)
Postfix的性能压测(PHP版) 发送测试:分别使用PHP Mail()函数和PHPMailler smtp协议发送邮件, 推送速率是指 发送个数/PHP程序运行时间, 发送速率是指 发送个数/( ...
- JSP 相关试题(一)
选择题 1.当用户请求jsp页面时,JSP引擎就会执行该页面的字节码文件响应客户的请求,执行字节码文件的结果是(C) A)发送一个JSP源文件到客户端 B)发送一个Java文件到客户端 C)发送 ...