【c++】生成浮点随机数

c++11：std::uniform_real_distribution<>直接求（尖括号不填默认生成double）

随机10个在1-2之间的浮点数

#include <random>
#include <iostream>

int main()
{
    std::random_device rd;  //Will be used to obtain a seed for the random number engine
    std::mt19937 gen(rd()); //Standard mersenne_twister_engine seeded with rd()
    std::uniform_real_distribution<> dis(1.0, 2.0);
    for (int n = ; n < ; ++n) {
        // Use dis to transform the random unsigned int generated by gen into a
        // double in [1, 2). Each call to dis(gen) generates a new random double
        std::cout << dis(gen) << ' ';
    }
    std::cout << '\n';
}

结果：

1.80829 1.15391 1.18483 1.38969 1.36094 1.0648 1.97798 1.27984 1.68261 1.57326

https://en.cppreference.com/w/cpp/numeric/random/uniform_real_distribution

c++11 之前：通过std::rand()和RAND_MAX间接求

如果要实现0-1之间随机浮点数的函数，可以如下：

double randf() {
     return (double)(rand()/(double)RAND_MAX);
} 

https://blog.csdn.net/enterlly/article/details/54310945