zsh & for loop bug

zsh & for loop bug

​for: command not found

syntax error near unexpected token do' do'

Unicode 编码问题

Error

#!/usr/bin/env bash

echo  emoji ^-v-^
# -e 换行
echo -e "\n"

arg1=$1
arg2=$2
arg3=$3
arg4=$4
arg5=$5
arg6=$6
arg7=$7
arg8=$8
arg9=$9
# >= 10, $n => ${n}
arg10=${10}
arg11=${11}
arg12=${12}

# echo $arg1
# echo $arg2
# echo $arg3
# echo $arg4
# echo $arg5
# echo $arg6
# echo $arg7
# echo $arg8
# echo $arg9
# echo $arg10
# echo $arg11
# echo $arg12
#  , 参数可以为空
all=$((arg1 + arg2 + arg3 + arg4 + arg5 + arg6 + arg7 + arg8 + arg9 + arg10 + arg11 + arg12))

# -e 换行
echo -e "\n"
echo $all

# -e 换行
echo -e "\n"

# \ 转义符
echo "\$* 参数整体:" $*
echo "\$@ 参数列表:" $@
echo "\$# 参数个数:" $#

​for i in "$*"
do
  echo "\$* 参数整体, 参数 i" $i
done

​for j in "$@"
do
  echo "\$@ 参数列表, 参数 j" $j
done

# DEMO
# ./for-loop.sh 1 2 3 4 5 6 7 8 9 10 11 12

# 55 + 23 = 78
# const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12];
# arr.reduce((acc, item) => acc += item, 0);

solutions

#!/usr/bin/env bash

echo  emoji ^-v-^
# -e 换行
echo -e "\n"

arg1=$1
arg2=$2
arg3=$3
arg4=$4
arg5=$5
arg6=$6
arg7=$7
arg8=$8
arg9=$9
# >= 10, $n => ${n}
arg10=${10}
arg11=${11}
arg12=${12}

# echo $arg1
# echo $arg2
# echo $arg3
# echo $arg4
# echo $arg5
# echo $arg6
# echo $arg7
# echo $arg8
# echo $arg9
# echo $arg10
# echo $arg11
# echo $arg12
#  , 参数可以为空
all=$((arg1 + arg2 + arg3 + arg4 + arg5 + arg6 + arg7 + arg8 + arg9 + arg10 + arg11 + arg12))

# -e 换行
echo -e "\n"
echo $all

# -e 换行
echo -e "\n"

# \ 转义符
echo "\$* 参数整体:" $*
echo "\$@ 参数列表:" $@
echo "\$# 参数个数:" $#

#  终止，结束，闭合 echo
echo ""

# ​for i in "$*" do echo "\$* 参数整体, 参数 i = $i" done
# ​for j in "$@" do echo "\$@ 参数列表, 参数 j" $j done

for i in "$*"
do
  echo "\$* 参数整体, 参数 i = $i"
done

for j in "$@"
do
  echo "\$@ 参数列表, 参数 j" $j
done

# DEMO
# ./for-loop.sh 1 2 3 4 5 6 7 8 9 10 11 12

# 55 + 23 = 78
# const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12];
# arr.reduce((acc, item) => acc += item, 0);

#!/usr/bin/env bash

echo " emoji ^-v-^"

# -e 换行, \n\r 两行 bug
# echo -e "\n"
# 换一行
echo ""

arg1=$1
arg2=$2
arg3=$3
arg4=$4
arg5=$5
arg6=$6
arg7=$7
arg8=$8
arg9=$9
# >= 10, $n => ${n}
arg10=${10}
arg11=${11}
arg12=${12}

# echo $arg1
# echo $arg2
# echo $arg3
# echo $arg4
# echo $arg5
# echo $arg6
# echo $arg7
# echo $arg8
# echo $arg9
# echo $arg10
# echo $arg11
# echo $arg12
#  , 参数可以为空
all=$((arg1 + arg2 + arg3 + arg4 + arg5 + arg6 + arg7 + arg8 + arg9 + arg10 + arg11 + arg12))

echo $all

# -e 换行, \n\r 两行 bug
# echo -e "\n"
# 换一行
echo ""

# \ 转义符
echo "\$* 参数整体:" $*
echo "\$@ 参数列表:" $@
echo "\$# 参数个数:" $#

#  终止，结束，闭合 echo "" $var
# echo ""

# ​for i in "$*" do echo "\$* 参数整体, 参数 i = $i" done
# ​for j in "$@" do echo "\$@ 参数列表, 参数 j" $j done

for i in "$*"
do
  #  终止，结束，闭合 echo "$var"
  # echo "\$* 参数整体, 参数 i = $i"
  echo "\$* 参数整体, 参数 i = " $i
done

for j in "$@"
do
  # not close echo "" $var
  echo "\$@ 参数列表, 参数 j" $j
  # echo "\$@ 参数列表, 参数 j $j"
done

# DEMO
# ./for-loop.sh 1 2 3 4 5 6 7 8 9 10 11 12

# 55 + 23 = 78
# const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12];
# arr.reduce((acc, item) => acc += item, 0);

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