sort algorithms
//todo
#include<iostream>
void swap(int *a, int *b){int temp = *a; *a = *b; *b = temp;}
void print_array(int *arr, int len) { for (int i = ; i < len; i++) std::cout << arr[i] << " , "; }
// swap sort (bubble sort), bubble the largest item to top of list, impractical
void bubble_sort(int arr[], int len)
{
bool need_sort = true;
while (need_sort)
{
need_sort = false;
for (int i = ; i < len - ; i++)
{
if (arr[i] < arr[i + i]){swap(arr+i, arr+i + );need_sort = true;}
}
}
}
// selection sort, select the largest one, and put it in the top, just need O(n) insert operation!!!
void select_sort(int arr[], int len)
{
for (int i = ; i < len - ; i++)
{
int index = i;
for (int j = i + ; j < len; j++)
{
if (arr[j] > arr[index]) index = j;
}
swap(arr+i, arr+index);
}
}
// the only advantage of both bubble sort and selection sort is easy to implement, should not use it
// insert sort, choose item in list one and insert into another in right order
// efficient for small lists and mostly-sorted list
void insert_sort(int arr[], int len)
{
for (int i = ; i < len-; i++)
{
int temp = arr[i + ];
int j = i;
for (; j >= && (arr[j] < temp); j--)
{
arr[j+] =arr[j];
}
if (j < i) arr[j+] = temp;
}
}
// as the result list is sorted, insert one new item is same to : put the new item in the top,
// bubble (swap) it to the right position (just need one-time bubbling through the list)
void insert_sort2(int arr[], int len)
{
for (int i = ; i < len; i++)
{
for (int j = i - ; j >= && (arr[j] < arr[j + ]); j--)
{
swap(arr + j, arr + j + );
}
}
}
// shell sort, combine insert sort and group (because insert sort is efficient when the list is mostly-sorted,
// one of the fastest algorithms for small number of elements( < 1000 ), and it needs little momery
// unlike efficient sorting algorithms, Shellsort does not require use of the call stack, making it useful in embedded systems where memory is at a premium
void shell_sort(int arr[], int len)
{
for (int gap = len / ; gap >; gap /= )
{
for (int i = ; i < gap; i++)
{
for (int k = i + gap; k < len; k += gap)
{
for (int j = k - gap; j >= && (arr[j] < arr[j + gap]); j -= gap) swap(arr + j, arr + j + gap);
}
}
}
}
// merge sort, recursion and double memory of data
void merge_sorted_array(int a[], int lena, int b[], int lenb, int c[])
{
int i(), j(), m();
while (i < lena && j << lenb)
{
if (a[i] < b[j]) c[m++] = a[i++];
else c[m++] = b[j++];
}
while (i < lena) c[m++] = a[i++];
while (j < lenb) c[m++] = b[j++];
}
void merge_array(int a[], int first,int mid, int last, int temp[])
{
int i(first), j(mid), m();
while (i < mid && j <=last)
{
if (a[i] < a[j]) temp[m++] = a[i++];
else temp[m++] = a[j++];
}
while (i < mid) temp[m++] = a[i++];
while (j <=last) temp[m++] = a[j++];
for (i = first, m = ; i <= last;) a[i++] = temp[m++];
}
void merge_sort(int a[], int first_index, int last_index, int temp[])
{
if (last_index>first_index)
{
int mid = (first_index + last_index) / ;
merge_sort(a, first_index, mid, temp);
merge_sort(a, mid + , last_index, temp);
merge_array(a, first_index, mid+, last_index, temp);
}
}
// quick sort, choose a pivot, put all elements smaller before it!
// Typically, quicksort is significantly faster in practice than other Θ(nlogn) algorithms
// in-place, need less swap than merge-sort
void quick_sort(int a[], int first, int last)
{
if (!(first < last)) return;
int i = first, j = last, temp = a[i];
while (i < j)
{
while (i < j && temp < a[j]) j--;
if (i < j) a[i++] = a[j];
while (i < j && a[i] < temp) i++;
if (i < j) a[j--] = a[i];
}
a[i] = temp;
quick_sort(a, first, i - );
quick_sort(a, i + , last);
}
int main()
{
int array01[] = { , , , , , , , , };
int temparr[] = { };
quick_sort(array01, ,);
print_array(array01, );
}
sort algorithms的更多相关文章
- Basic Sort Algorithms
1. Bubble Sort public void bubbleSort(int[] arr) { boolean swapped = true; int j = 0; int tmp; while ...
- Advanced Sort Algorithms
1. Merge Sort public class Mergesort { private int[] numbers; private int[] helper; private int numb ...
- Javascript数组算法和技巧总结
Js-arrayMethod https://github.com/HerbertKarajan/Js-arrayMethod List unique an array 数组去重 random str ...
- Java性能提示(全)
http://www.onjava.com/pub/a/onjava/2001/05/30/optimization.htmlComparing the performance of LinkedLi ...
- Java Concurrency - invokeAny & invokeAll
Running multiple tasks and processing the first result A common problem in concurrent programming is ...
- AOJ/初等排序习题集
ALDS1_1_D-MaximumProfit. Codes: //#define LOCAL #include <cstdio> #include <algorithm> u ...
- LeetCode Questions List (LeetCode 问题列表)- Java Solutions
因为在开始写这个博客之前,已经刷了100题了,所以现在还是有很多题目没有加进来,为了方便查找哪些没加进来,先列一个表可以比较清楚的查看,也方便给大家查找.如果有哪些题目的链接有错误,请大家留言和谅解, ...
- BookNote: Refactoring - Improving the Design of Existing Code
BookNote: Refactoring - Improving the Design of Existing Code From "Refactoring - Improving the ...
- Lazarus教程 中文版后续给出
市面上有介绍Delphi的书籍(近来Delphi的书也是越来越少了),但没有一本系统的介绍Lazarus的书,这本书是网上的仅有的一本Lazarus教程,目前全部是英文,不过我已经着手开始翻译,争取尽 ...
随机推荐
- 在Asp.Net Core中使用DI的方式使用Hangfire构建后台执行脚本
最近项目中需要用到后台Job,原有在Windows中我们会使用命令行程序结合计划任务或者直接生成Windows Service,现在.Net Core跨平台了,虽然Linux下也有计划任务,但跟原有方 ...
- codeforces#1136 C. Nastya Is Transposing Matrices(找规律)
题意:给出两个n*m的矩阵,每次操作可以让一个正方形矩阵行列交换.问,在无限次操作下,第一个矩阵能否变成第二个矩阵 分析:先把操作限定在2*2的矩阵中.这样对角线上的元素就可以随意交换.也就是说,如果 ...
- ubuntu 18.04安装pytorch、cuda、cudnn等
版权声明:本文为博主原创文章,欢迎转载,并请注明出处.联系方式:460356155@qq.com ubuntu 16.04用了1年多了,18.04版已经发布也半年了,与时俱进,重装Linux系统,这里 ...
- 如何搭建SVN的客户端和使用
1.下载安装TortoiseSVN 首先我们需要从官方网站下载TortoiseSVN客户端工具 可以选择32位和64位.也可以直接使用搜索引擎搜索TortoiseSVN 也会出现直接的下载方式.这里不 ...
- 关于oracle sql语句查询时表名和字段名要加双引号的问题详解
转自:http://www.2cto.com/database/201504/387184.html 作为oracle的初学者相信大家一定会遇到这个问题,如图: 明明就是navicat可视化创建了表, ...
- Mysql——Navicat 连接MySQL 8.0.11 出现2059错误
原因 mysql8 之前的版本中加密规则是mysql_native_password,而在mysql8之后,加密规则是caching_sha2_password 解决 更改加密规则: mysql -u ...
- 在Django中使用logging模块
一.Django logging配置 1.在setting.py中配置 # 日志文件存放路径 BASE_LOG_DIR = os.path.join(BASE_DIR, "log" ...
- Python爬虫之一
1. 爬虫的选取:scrapy和requests+beautifuisoup scrapy是框架,而requests和beautifulsoup是库.scrapy框架是可以加如requests和bea ...
- 3537. 【NOIP2013提高组day2】华容道(搜索 + 剪枝)
Problem 给出一个类似华容道的图.\(q\)次询问,每次给你起始点,终止点,空格位置,让你求最少步数 \(n,m\le 30, q\le 500\). Soultion 一道智障搜索题. 弱智想 ...
- 浏览器开发者工具----F12 功能介绍
笔者技巧: 看了些其它回答,有些是用来扒图片的,有些是写爬虫的(这个不要看Elements,因为浏览器会对一些不符合规范的标签做补全或者其它处理,最好是Ctrl+U). 图片的话就不要看Network ...