[LeetCode]Copy List with Random Pointer &Clone Graph 复杂链表的复制&图的复制
/**
* Definition for singly-linked list with a random pointer.
* struct RandomListNode {
* int label;
* RandomListNode *next, *random;
* RandomListNode(int x) : label(x), next(NULL), random(NULL) {}
* };
*/
class Solution {//为了可以高速定位某个节点,採用确定性映射的方式,将复制链表的节点作为原链表相应节点的下一个节点
public:
RandomListNode *copyRandomList(RandomListNode *head) {
//每一个节点指向其复制链表相应的节点,从而可以高速定位该节点
if(!head)return NULL;
RandomListNode *p,*q;
p=head;
while(p){
q=new RandomListNode(p->label);
q->next=p->next;
p->next=q;
p=q->next;
}
p=head;
while(p){
q=p->next;
if(p->random)
q->random=p->random->next;
p=q->next;
}
p=head;
RandomListNode*head2=p->next;
q=head2;
while(p){
p->next=q->next;
p=p->next;
if(p){
q->next=p->next;
q=q->next;
}
}
return head2;
}
};
Clone Graph
:
类似的,对于图的复制,必须找到一种能够对新图中节点进行映射,能高速定位新节点的地址,从而使新节点指向新节点。这里採用map映射。考虑到图节点的label可能反复(本题不反复),而节点地址不反复,所以以新旧节点为键值对。
/**
* Definition for undirected graph.
* struct UndirectedGraphNode {
* int label;
* vector<UndirectedGraphNode *> neighbors;
* UndirectedGraphNode(int x) : label(x) {};
* };
*/
class Solution {
public:
map<UndirectedGraphNode*,UndirectedGraphNode*>mp;
map<UndirectedGraphNode*,UndirectedGraphNode*>::iterator bg;
UndirectedGraphNode* dfs(UndirectedGraphNode*p){
if(!p)return NULL;
if((bg=mp.find(p))!=mp.end())
return bg->second;
UndirectedGraphNode *q;
mp[p]=q=new UndirectedGraphNode(p->label);
for(int i=0,m=p->neighbors.size();i<m;++i){
q->neighbors.push_back(dfs(p->neighbors[i]));
}
return q;
}
UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
if(!node)return NULL;
dfs(node);
return mp[node];
}
};
[LeetCode]Copy List with Random Pointer &Clone Graph 复杂链表的复制&图的复制的更多相关文章
- [LeetCode] Copy List with Random Pointer 拷贝带有随机指针的链表
A linked list is given such that each node contains an additional random pointer which could point t ...
- [leetcode]Copy List with Random Pointer @ Python
原题地址:https://oj.leetcode.com/problems/copy-list-with-random-pointer/ 题意: A linked list is given such ...
- Leetcode Copy List with Random Pointer(面试题推荐)
给大家推荐一道leetcode上的面试题,这道题的详细解说在<剑指offer>的P149页有思路解说.假设你手头有这本书.建议翻阅. 题目链接 here A linked list is ...
- LeetCode——Copy List with Random Pointer
A linked list is given such that each node contains an additional random pointer which could point t ...
- LeetCode——Copy List with Random Pointer(带random引用的单链表深拷贝)
问题: A linked list is given such that each node contains an additional random pointer which could poi ...
- Leetcode Copy List with Random Pointer
A linked list is given such that each node contains an additional random pointer which could point t ...
- [Leetcode] Copy list with random pointer 对带有任意指针的链表深度拷贝
A linked list is given such that each node contains an additional random pointer which could point t ...
- LeetCode – Copy List with Random Pointer
A linked list is given such that each node contains an additional random pointer which could point t ...
- 【LeetCode】138. Copy List with Random Pointer 复制带随机指针的链表 解题报告(Python)
作者: 负雪明烛 id: fuxuemingzhu 个人公众号:负雪明烛 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https:/ ...
随机推荐
- 【转】Robot Framework 快速入门
目录 介绍 概述 安装 运行demo 介绍样例应用程序 测试用例 第一个测试用例 高级别测试用例 数据驱动测试用例 关键词keywords 内置关键词 库关键词 用户定义关键词 变量 定义变量 使用变 ...
- 前端project师的修真秘籍(css、javascript和其他)
以我的经验,大部分技术,熟读下列四类书籍就可以. 入门,用浅显的语言和方式讲述正确的道理和方法,如head first系列 全面,巨细无遗地探讨每一个细节,遇到疑难问题时往往能够在这里得到理论解答,如 ...
- capturing self strongly in this block is likely to lead to a retain cycle
一个用Block实例变量语法,当有一个参考的实例变量,常引起retain cycle. capturing self strongly in this block is likely to lead ...
- [Visual Studio]透过Visual Studio 2012的选择性贴上将XML与JSON直接转成对应的类别
原文:[Visual Studio]透过Visual Studio 2012的选择性贴上将XML与JSON直接转成对应的类别 在开发专案时若碰到要串接服务或是他人的API,常常避免不了都要面对XML或 ...
- hdu3480二维斜率优化DP
Division Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 999999/400000 K (Java/Others) Tota ...
- strtok、strtok_s、strtok_r 字符串切割函数
1.strtok函数 函数原型:char * strtok (char *str, const char * delimiters); 參数:str,待切割的字符串(c-string):delimit ...
- linux内核包转发过程(三)NIC帧接收分析
[版权声明:转载请保留源:blog.csdn.net/gentleliu.邮箱:shallnew*163.com] 每一个cpu都有队列来处理接收到的帧.都有其数据结构来处理入口和出口流量,因此.不同 ...
- SEO思维的优化源于生活
[回顾]无论哪个行业的,.学习技巧和操作非常简单,它主要是一个时间的问题?回到seo行业,操作和技能是非常easy学习,和seo入门是互联网行业最easy行业,不像有些人理解的代码,敲代码等,它必须基 ...
- 漂浮广告代码兼容ie、firefox,多个漂浮不冲突,调用只需两行代码
原文:漂浮广告代码兼容ie.firefox,多个漂浮不冲突,调用只需两行代码 将广告内容放在div中,设置一个id,然后用下面方法调用var adcls=new AdMove("div的id ...
- NYNU_省赛选拔题(5)
题目描述 P 的一家要出去旅游,买了当地的地图,发现各地分别由各个景点,若 P 想使家人分队去景点,尽快到达各个景点(必须所有景点),并且最终所有家人都到达 M 所在的景点. 你用程序告诉 P 最 ...