PAT甲级——A1042 Shuffling Machine
Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid "inside jobs" where employees collaborate with gamblers by performing inadequate shuffles, many casinos employ automatic shuffling machines. Your task is to simulate a shuffling machine.
The machine shuffles a deck of 54 cards according to a given random order and repeats for a given number of times. It is assumed that the initial status of a card deck is in the following order:
S1, S2, ..., S13,
H1, H2, ..., H13,
C1, C2, ..., C13,
D1, D2, ..., D13,
J1, J2
where "S" stands for "Spade", "H" for "Heart", "C" for "Club", "D" for "Diamond", and "J" for "Joker". A given order is a permutation of distinct integers in [1, 54]. If the number at the i-th position is j, it means to move the card from position i to position j. For example, suppose we only have 5 cards: S3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result will be: J2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result will be: C1, H5, S3, J2, D13.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer K (≤) which is the number of repeat times. Then the next line contains the given order. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print the shuffling results in one line. All the cards are separated by a space, and there must be no extra space at the end of the line.
Sample Input:
2
36 52 37 38 3 39 40 53 54 41 11 12 13 42 43 44 2 4 23 24 25 26 27 6 7 8 48 49 50 51 9 10 14 15 16 5 17 18 19 1 20 21 22 28 29 30 31 32 33 34 35 45 46 47
Sample Output:
S7 C11 C10 C12 S1 H7 H8 H9 D8 D9 S11 S12 S13 D10 D11 D12 S3 S4 S6 S10 H1 H2 C13 D2 D3 D4 H6 H3 D13 J1 J2 C1 C2 C3 C4 D1 S5 H5 H11 H12 C6 C7 C8 C9 S2 S8 S9 H10 D5 D6 D7 H4 H13 C5
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main()
{
int K, N = ;
vector<string>cards(N + ), res(N + ), temp(N + );
vector<int>n(N + );
for (int i = ; i <= N; ++i)
{
string s;
if (i <= )
s = "S" + to_string(i);
else if (i <= )
s = "H" + to_string(i - );
else if (i <= )
s = "C" + to_string(i - );
else if (i <= )
s = "D" + to_string(i - );
else
s = "J" + to_string(i - );
cards[i] = s;
}
cin >> K;
for (int i = ; i <= N; ++i)
cin >> n[i];
res = cards;
for (int i = ; i < K; ++i)
{
temp = res;
for (int j = ; j <= N; ++j)
res[n[j]] = temp[j];
}
for (int i = ; i <= N; ++i)
cout << res[i] << (i == N ? "" : " ");
return ;
}
PAT甲级——A1042 Shuffling Machine的更多相关文章
- PAT 甲级 1042 Shuffling Machine
https://pintia.cn/problem-sets/994805342720868352/problems/994805442671132672 Shuffling is a procedu ...
- PAT 甲级 1042 Shuffling Machine (20 分)(简单题)
1042 Shuffling Machine (20 分) Shuffling is a procedure used to randomize a deck of playing cards. ...
- PAT甲级——1042 Shuffling Machine
1042 Shuffling Machine Shuffling is a procedure used to randomize a deck of playing cards. Because s ...
- A1042. Shuffling Machine
Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techn ...
- A1042 Shuffling Machine (20)
1042 Shuffling Machine (20)(20 分) Shuffling is a procedure used to randomize a deck of playing cards ...
- PAT Advanced 1042 Shuffling Machine (20 分)(知识点:利用sstream进行转换int和string)
Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techn ...
- PAT(A) 1042. Shuffling Machine (20)
Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techn ...
- PAT A1042 Shuffling Machine
自己思路,没通过 #include <cstdio> #define N 54 int main() { #ifdef ONLINE_JUDGE #else freopen("1 ...
- PAT甲级题解分类byZlc
专题一 字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d& ...
随机推荐
- IK分词器插件
(1)源码 https://github.com/medcl/elasticsearch-analysis-ik (2)releases https://github.com/medcl/elast ...
- 基于token的验证
认证.权限和限制 身份验证是将传入请求与一组标识凭据(例如请求来自的用户或其签名的令牌)相关联的机制.然后 权限 和 限制 组件决定是否拒绝这个请求. 简单来说就是: 认证确定了你是谁 权限确定你能不 ...
- WEB前端使用的CSS3选择器
首先说first-child与last-child,这两个选择器很容易明白,就是父元素下的第一个子元素和最后一个子元素.而nth-child和nth-last-child则是父元素下指定序号的子元素, ...
- Daemon 守护线程(27-11)
t2.setDaemon(True)不再等待里面的sleep(5). 当设成setDaemon(True)这个线程就不等了. 例子一: import threadingfrom time import ...
- Java并发编程中的若干核心技术,向高手进阶!
来源:http://www.jianshu.com/p/5f499f8212e7 引言 本文试图从一个更高的视角来总结Java语言中的并发编程内容,希望阅读完本文之后,可以收获一些内容,至少应该知道在 ...
- POJ 2398 map /// 判断点与直线的位置关系
题目大意: poj2318改个输出 输出 a: b 即有a个玩具的格子有b个 可以先看下poj2318的报告 用map就很方便 #include <cstdio> #include < ...
- 阻止a标签跳转/刷新
<a href='javascript:;' onClick='functionA()'>点击</a> //注意":"."’":均需为英 ...
- java笔试之字符逆序(二)
与字符逆序(一)不同,句子逆序,单词顺序.例如:I am a student 输出为student a am I. 想法:先字符串句子逆序,然后针对每个单词再逆序一遍. package test; i ...
- umount:将文件设备卸载
[root@centos57 ~]# umount /dev/hda1 用设备文件名来卸载 [root@centos57 ~]# umount /aixi 用挂 ...
- gnome3 修改桌面背景图片模式
修改背景图片,可以在 桌面右键 选择"修改壁纸",选择"background"(背景),这里没有设定背景图片模式. 可以在 “应用程序”->"工 ...