I love sneakers!

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4765    Accepted Submission(s): 1950

Problem Description
After months of hard working, Iserlohn finally wins awesome amount of scholarship. As a great zealot of sneakers, he decides to spend all his money on them in a sneaker store.

There are several brands of sneakers that Iserlohn wants to collect, such as Air Jordan and Nike Pro. And each brand has released various products. For the reason that Iserlohn is definitely a sneaker-mania, he desires to buy at least one product for each brand.
Although the fixed price of each product has been labeled, Iserlohn sets values for each of them based on his own tendency. With handsome but limited money, he wants to maximize the total value of the shoes he is going to buy. Obviously, as a collector, he won’t buy the same product twice.
Now, Iserlohn needs you to help him find the best solution of his problem, which means to maximize the total value of the products he can buy.
 
Input
Input contains multiple test cases. Each test case begins with three integers 1<=N<=100 representing the total number of products, 1 <= M<= 10000 the money Iserlohn gets, and 1<=K<=10 representing the sneaker brands. The following N lines each represents a product with three positive integers 1<=a<=k, b and c, 0<=b,c<100000, meaning the brand’s number it belongs, the labeled price, and the value of this product. Process to End Of File.
 
Output
For each test case, print an integer which is the maximum total value of the sneakers that Iserlohn purchases. Print "Impossible" if Iserlohn's demands can’t be satisfied.
 
Sample Input
5 10000 3 1 4 6 2 5 7 3 4 99 1 55 77 2 44 66
 
Sample Output
255
 

HD3033I love sneakers!(分组背包+不懂)的更多相关文章

  1. I love sneakers!(分组背包HDU3033)

    I love sneakers! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) ...

  2. hdu 3033 I love sneakers! 分组背包

    I love sneakers! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) ...

  3. hdu 3033 I love sneakers!(分组背包+每组至少选一个)

    I love sneakers! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) ...

  4. hdu3033 I love sneakers! 分组背包变形

    分组背包要求每一组里面只能选一个,这个题目要求每一组里面至少选一个物品. dp[i, j] 表示前 i 组里面在每组至少放进一个物品的情况下,当花费 j 的时候,所得到的的最大价值.这个状态可以由三个 ...

  5. HDU3033I love sneakers!(分组背包)

    http://acm.hdu.edu.cn/showproblem.php?pid=3033 本题的意思就是说现在有n种牌子的鞋子,每种品牌有一些不同的鞋,每双鞋子都有一个特定的权值,现在要求每种品牌 ...

  6. hdu3033 I love sneakers! 分组背包变形(详解)

    这个题很怪,一开始没仔细读题,写了个简单的分组背包交上去,果不其然WA. 题目分析: 分组背包问题是这样描述的:有K组物品,每组 i 个,费用分别为Ci ,价值为Vi,每组物品是互斥的,只能取一个或者 ...

  7. hdu3033I love sneakers! (分组背包,错了很多次)

    Problem Description After months of hard working, Iserlohn finally wins awesome amount of scholarshi ...

  8. HDU3033 I love sneakers!———分组背包

    这题的动态转移方程真是妙啊,完美的解决了每一种衣服必须买一件的情况. if(a[x][i-c[x][j].x]!=-1) a[x][i]=max(a[x][i],a[x][i-c[x][j].x]+c ...

  9. 【HDU】I love sneakers!(分组背包)

    看了许多的题解,都有题目翻译,很不错,以后我也这样写.直接翻译样例: /*鞋子的数量N[1, 100]; 拥有的金钱M[1, 1w]; 品牌数目[1, 10]*/ /*以下四行是对于每双鞋的描述*/ ...

随机推荐

  1. LoadRunner免费公开课,惠普金牌讲师亲授

    [开课时间]:9月13日 下午2:00—4:00(暂定)[活动费用]:免费[主办单位]:慧都学院[课程形式]:网络在线公开课 LoadRunner简介惠普软件测试解决方案LoadRunner测试实例答 ...

  2. 30分钟让网站支持HTTPS

    对于一个良好和安全的网络——并且也为了更快的性能,新的API网络例如Service Workers,更佳的搜索排名,还有——在你的网站上使用HTTPS是关键.这里我会指导大家如何轻松搞定. 我不是安全 ...

  3. iOS获取app图标和启动图片名字(AppIcon and LaunchImage's name)

    在某种场景下,可能我们需要获取app的图标名称和启动图片的名称.比如说app在前台时,收到了远程通知但是通知栏是不会有通知提醒的,这时我想做个模拟通知提示,需要用到icon名称:再比如在加载某个控制器 ...

  4. 细分java环境中的JDK、JVM、JRE

    细分java环境中的JDK.JVM.JRE 近来小看了下Android,扑面而来一堆概念JDK.JVM.JRE.SDK.NDK.ADT.缕了一下,其中JDK.JVM.JRE是java环境的东西,而SD ...

  5. [笔记]ubuntu安装flashplayer

    为firefox安装: 下载tar.gz压缩包:http://get.adobe.com/cn/flashplayer/ 解压:tar -xvxf install_flash_player_11_li ...

  6. Windows批处理:自动开关程序

    公司有台14年组装的PC,时常无故重启,所以编写了个然并卵的批处理来测试稳定性. 打开程序.bat @echo off title Start Software color 2F : "C: ...

  7. codevs 1082 线段树区间求和

    codevs 1082 线段树练习3 链接:http://codevs.cn/problem/1082/ sumv是维护求和的线段树,addv是标记这歌节点所在区间还需要加上的值. 我的线段树写法在运 ...

  8. webgl巧妙方式写着色器代码

    var VSHADER_SOURCE = function(){ /* void main(){ gl_Position = vec4(0.0,0.0,0.0,1.0); gl_PointSize = ...

  9. 基于modelsim-SE的专业进阶仿真流程

    基于modelsim-SE的专业进阶仿真流程 通过<基于modelsim-SE的简单仿真流程>和<调用altera IP核的仿真流程>是否感受到仿真流程中的繁琐步骤,特别是在m ...

  10. 轻量级jQuery语法高亮代码高亮插件jQuery Litelighter。

    <!DOCTYPE html><html><head><meta charset="UTF-8" /><title>jQ ...