Description

New convocation of The Fool Land's Parliament consists of N delegates. According to the present regulation delegates should be divided into disjoint groups of different sizes and every day each group has to send one delegate to the conciliatory committee. The composition of the conciliatory committee should be different each day. The Parliament works only while this can be accomplished. 
You are to write a program that will determine how many delegates should contain each group in order for Parliament to work as long as possible. 

Input

The input file contains a single integer N (5<=N<=1000 ).

Output

Write to the output file the sizes of groups that allow the Parliament to work for the maximal possible time. These sizes should be printed on a single line in ascending order and should be separated by spaces.

Sample Input

7

Sample Output

3 4

POJ 1032问题描述的更多相关文章

  1. poj 1032 Parliament 【思维题】

    题目地址:http://poj.org/problem?id=1032 Parliament Time Limit: 1000MS   Memory Limit: 10000K Total Submi ...

  2. POJ 1528问题描述

    Description From the article Number Theory in the 1994 Microsoft Encarta: ``If a, b, c are integers ...

  3. POJ 1041问题描述

    Description Little Johnny has got a new car. He decided to drive around the town to visit his friend ...

  4. POJ 1039问题描述

    Description The GX Light Pipeline Company started to prepare bent pipes for the new transgalactic li ...

  5. POJ 1035题目描述

    Description You, as a member of a development team for a new spell checking program, are to write a ...

  6. POJ 1028题目描述

    Description Standard web browsers contain features to move backward and forward among the pages rece ...

  7. Poj 1032 分类: Translation Mode 2014-04-04 09:09 111人阅读 评论(0) 收藏

    Parliament Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 16521   Accepted: 6975 Descr ...

  8. (Relax 水题1.2)POJ 1032 Parliament(将n分解成若干个互不相等的整数的和,并且是这些整数的乘积最大)

    题意:给出一个数n,将其拆分为若干个互不相等的数字的和,要求这些数字的乘积最大. 分析:我们可以发现任何一个数字,只要能拆分成两个大于1的数字之和,那么这两个数字的乘积一定大于等于原数.也就是说,对于 ...

  9. 【贪心】 poj 1032 和为n的若干数最大乘积

    给出n,把n分解为若干不相同数之和,使之乘积最大.贪心,Discuss里面的思路:把n分解为从2开始的连续整数,如果有多,则从高位开始依次加1.如26,我们得到2+3+4+5+6,此时还剩余6(26- ...

随机推荐

  1. 安装rkhunter

    #!/bin/bash if [ ! -d /soft ];thenmkdir /soft fiwhich rkhunterif [ $? -eq 0 ];then echo "rkhunt ...

  2. [译]- 6-1 排列窗体上的控件(Laying Out Widgets on a Form)

     排列窗体上的控件(Laying Out Widgets on a Form) 中英文对照:form(窗体),layout(布局或者排列,意思是进行窗体上控件的排列的过程,如大小位置等) absolu ...

  3. for循环的时候是按照数字递增会造成一些元素被遗漏

    $test_array=array(1,2,3,4,4,5,5,6); $test_array_unique=array_unique($test_array); print_r($test_arra ...

  4. .net 开发的奇淫巧计

    随机数 Random random = new Random(( int)DateTime .Now.Ticks & 0x0000FFFF); 如何让ASP.NET Web API显示完整的错 ...

  5. eclipse远程调试

    -Xdebug -Xrunjdwp:transport=dt_socket,address=127.0.0.1:8000Eclipse 菜单上的 Window > Preferences > ...

  6. PAT 基础编程题 4-11 求自定类型元素序列的中位数(希尔排序)

    4-11 求自定类型元素序列的中位数   (25分) 本题要求实现一个函数,求N个集合元素A[]的中位数,即序列中第\lfloor N/2 +1\rfloor⌊N/2+1⌋大的元素.其中集合元素的类型 ...

  7. FZU 2028 BFS+vector

    一个普通的bfs 如果不看样例和input的解释... 四个0真是神样例 又被input误导 以为每个点都按顺序有标号 传送门的终点给的是一个点的标号 然后结果是什么呢?无尽的runtime erro ...

  8. Java SSH库使用简介:Apache sshd和JSch(Java Secure Channel)

    1.Apache sshd Apache sshd是一个SSH协议的100%纯Java库,支持客户端和服务器.sshd库基于Apache MINA项目(可伸缩高性能的异步IO库). 官方网站:http ...

  9. 第十章:鸟哥的Linux私房菜

    第十章.vim程式编辑器 1. vi与vim 1.1 为何要学vim2. vi的使用 2.1 简易执行范例 2.2 按键说明 2.3 一个案例的练习 2.4 vim的暂存档.救援回复与开启时的警告讯息 ...

  10. 做了一个简易的git 代码自动部署脚本

    做了一个简易的git 代码自动部署脚本 http://my.oschina.net/caomenglong/blog/472665 发表于2个月前(2015-06-30 21:08)   阅读(200 ...