POJ 1041问题描述
Description
The streets in Johnny's town were named by integer numbers from 1 to n, n < 1995. The junctions were independently named by integer numbers from 1 to m, m <= 44. No junction connects more than 44 streets. All junctions in the town had different numbers. Each street was connecting exactly two junctions. No two streets in the town had the same number. He immediately started to plan his round trip. If there was more than one such round trip, he would have chosen the one which, when written down as a sequence of street numbers is lexicographically the smallest. But Johnny was not able to find even one such round trip.
Help Johnny and write a program which finds the desired shortest round trip. If the round trip does not exist the program should write a message. Assume that Johnny lives at the junction ending the street appears first in the input with smaller number. All streets in the town are two way. There exists a way from each street to another street in the town. The streets in the town are very narrow and there is no possibility to turn back the car once he is in the street
Input
Output
Sample Input
1 2 1
2 3 2
3 1 6
1 2 5
2 3 3
3 1 4
0 0
1 2 1
2 3 2
1 3 3
2 4 4
0 0
0 0
Sample Output
1 2 3 5 4 6
Round trip does not exist.
POJ 1041问题描述的更多相关文章
- poj 1041(欧拉回路+输出字典序最小路径)
题目链接:http://poj.org/problem?id=1041 思路:懒得写了,直接copy吧:对于一个图可以从一个顶点沿着边走下去,每个边只走一次,所有的边都经过后回到原点的路.一个无向图存 ...
- [POJ 1041] John's Trip
[题目链接] http://poj.org/problem?id=1041 [算法] 欧拉回路[代码] #include <algorithm> #include <bitset&g ...
- poj 1041 John's trip——欧拉回路字典序输出
题目:http://poj.org/problem?id=1041 明明是欧拉回路字典序输出的模板. 优先队列存边有毒.写跪.学习学习TJ发现只要按边权从大到小排序连边就能正常用邻接表了! 还有一种存 ...
- POJ 1528问题描述
Description From the article Number Theory in the 1994 Microsoft Encarta: ``If a, b, c are integers ...
- POJ 1039问题描述
Description The GX Light Pipeline Company started to prepare bent pipes for the new transgalactic li ...
- POJ 1035题目描述
Description You, as a member of a development team for a new spell checking program, are to write a ...
- POJ 1032问题描述
Description New convocation of The Fool Land's Parliament consists of N delegates. According to the ...
- POJ 1028题目描述
Description Standard web browsers contain features to move backward and forward among the pages rece ...
- poj 1041 John's trip 欧拉回路
题目链接 求给出的图是否存在欧拉回路并输出路径, 从1这个点开始, 输出时按边的升序输出. 将每个点的边排序一下就可以. #include <iostream> #include < ...
随机推荐
- Error 2147943712 during task creation
In a Windows 2008 server, when you confirm the creation of a new task, you may obtain the following ...
- PHP 表单添加隐藏 Token 阻止外部提交
Token 法:通过一个隐藏可变的 Token 加大攻击的难度,每次提交都需要和服务器校对,如果不通过,则为外部提交(也可以通过 session + 隐藏域来验证). 代码: form.php < ...
- WampServer 在 httpd.conf 中配置多站点 (IP 配置法:不用每次修改 hosts 文件 + 域名配置法 )
因为要用 ThinkPHP 的当前最新版本 3.2.2,对应要求 PHP 的版本要高于 5.3.0,所以安装了 WampServer 2.2 ( Apache 2.2.21,PHP 5.3.10,My ...
- 初步理解Java的三大特性——封装、继承和多态
声明:整理自网络,如有雷同,请联系博主处理 一.封装 封装从字面上来理解就是包装的意思,专业点就是信息隐藏,是指利用抽象数据类型将数据和基于数据的操作封装在一起,使其构成一个不可分割的独立实体,数据被 ...
- a bitwise operation 广告投放监控
将随着时间不断增大的数字N个依次编号为1到N的N个球,颜色每次随机为红黑蓝,时间上先后逐个放入篮子中,计算离现在最近的24个球的红.黑.蓝颜色数 广告投放监控 a bitwise operation ...
- 五 mybatis的SqlMapConfig.xml详解
SqlMapConfig.xml <?xml version="1.0" encoding="UTF-8" ?> <!DOCTYPE conf ...
- 蓝牙的SDP协议总结
1.概念 SDP协议让客户机的应用程序发现存在的服务器应用程序提供的服务以及这些服务的属性.SDP只提供发现服务的机制,不提供使用这些服务的方法.每个蓝牙设备都需要一个SDP Service, ...
- Redis学习笔记(1)-Key
package cn.com; import java.text.ParseException; import java.util.List; import java.util.Set; import ...
- 介绍UDF,以及完成大小写的转换
一:概述 1.UDF 用户自定义函数,用java实现自定义的需求 2.UDF的类型 udf:一进一出 udaf:多进一出 udtf:一进多出 3.udf的实现步骤 继承UDF类 实现evaluate的 ...
- javaScript没有块级作用域
1.如下,变量i,j,k 的作用域是相同的. function test(obj){ var i= 0; if(typeof obj == "object"){ var j = 0 ...