Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

Note: You can only move either down or right at any point in time.

解题思路:

Unique Paths题目非常类似,区别在于本题为有权值路径;

解题方法基本一致,还是通过数组迭代方法,使用n个额外空间的动态规划思路,区别在于迭代前需要计算数组初始值。

代码:

 class Solution {
public:
int minPathSum(vector<vector<int>>& grid) {
int m = grid.size();
int n = grid[].size();
vector<int> col(grid.back()); for (int i = n - ; i >= ; --i)
col[i] += col[i+]; for (int i = m - ; i >= ; --i) {
col[n-] += grid[i][n-];
for (int j = n - ; j >= ; --j) {
col[j] = grid[i][j] + min(col[j], col[j+]);
}
} return col[];
}
};

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