1066 Root of AVL Tree (25分)(AVL树的实现)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore this property. Figures 1-4 illustrate the rotation rules.
Now given a sequence of insertions, you are supposed to tell the root of the resulting AVL tree.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (≤) which is the total number of keys to be inserted. Then N distinct integer keys are given in the next line. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print the root of the resulting AVL tree in one line.
Sample Input 1:
5
88 70 61 96 120
Sample Output 1:
70
Sample Input 2:
7
88 70 61 96 120 90 65
Sample Output 2:
88
题目分析:写一个AVL树 背课文是好的 但也要理解清除AVL树的原理 之后还要学习各种平衡树 如红黑树什么的
#define _CRT_SECURE_NO_WARNINGS
#include <climits>
#include<iostream>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<algorithm>
#include<string>
#include<cmath>
using namespace std;
typedef struct TNode* Tree;
struct TNode {
int Data;
Tree TL;
Tree TR;
int Height; //要初始化为-1;
};
int GetHeight(Tree T) {
if (T)
return T->Height;
else
return -;
}
Tree singleLeftRotate(Tree T) {
Tree TL = T->TL;
T->TL = TL->TR;
TL->TR = T;
T->Height = max(GetHeight(T->TL), GetHeight(T->TR)) + ;
TL->Height = max(GetHeight(TL->TL), GetHeight(TL->TR)) + ;
return TL;
}
Tree singleRightRotate(Tree T) {
Tree TR = T->TR;
T->TR = TR->TL;
TR->TL = T;
T->Height = max(GetHeight(T->TL), GetHeight(T->TR)) + ;
TR->Height = max(GetHeight(TR->TL), GetHeight(TR->TR)) + ;
return TR;
}
Tree doubleLeftRightRotate(Tree T) {
T->TL = singleRightRotate(T->TL);
return singleLeftRotate(T);
}
Tree doubleRightLeftRotate(Tree T) {
T->TR = singleLeftRotate(T->TR);
return singleRightRotate(T);
}
Tree Insert(Tree T,int data) {
if (!T)
{
T = new TNode();
T->Data = data;
T->Height = ;
T->TL = T->TR = NULL;
}
else if (data > T->Data) {
T->TR = Insert(T->TR, data);
T->Height = max(GetHeight(T->TL), GetHeight(T->TR)) + ;
if (GetHeight(T->TR) - GetHeight(T->TL) == ) {
if (data > T->TR->Data)
T=singleRightRotate(T);
else
T=doubleRightLeftRotate(T);
}
}
else {
T->TL = Insert(T->TL, data);
T->Height = max(GetHeight(T->TL), GetHeight(T->TR)) + ;
if (GetHeight(T->TL) - GetHeight(T->TR) == ) {
if (data < T->TL->Data)
T=singleLeftRotate(T);
else
T=doubleLeftRightRotate(T);
}
}
return T;
} int main()
{
int N;
Tree T = NULL;
int data;
cin >> N;
for (int i = ; i < N; i++)
{
cin >> data;
T = Insert(T, data);
}
cout << T->Data;
}
1066 Root of AVL Tree (25分)(AVL树的实现)的更多相关文章
- PAT 甲级 1066 Root of AVL Tree (25 分)(快速掌握平衡二叉树的旋转,内含代码和注解)***
1066 Root of AVL Tree (25 分) An AVL tree is a self-balancing binary search tree. In an AVL tree, t ...
- PAT甲级:1066 Root of AVL Tree (25分)
PAT甲级:1066 Root of AVL Tree (25分) 题干 An AVL tree is a self-balancing binary search tree. In an AVL t ...
- PTA 04-树5 Root of AVL Tree (25分)
题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/668 5-6 Root of AVL Tree (25分) An AVL tree ...
- 04-树5 Root of AVL Tree (25 分)
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child sub ...
- 【PAT甲级】1066 Root of AVL Tree (25 分)(AVL树建树模板)
题意: 输入一个正整数N(<=20),接着输入N个结点的值,依次插入一颗AVL树,输出最终根结点的值. AAAAAccepted code: #define HAVE_STRUCT_TIMESP ...
- pat 甲级 1066. Root of AVL Tree (25)
1066. Root of AVL Tree (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue An A ...
- 04-树4. Root of AVL Tree (25)
04-树4. Root of AVL Tree (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue An A ...
- pat1066. Root of AVL Tree (25)
1066. Root of AVL Tree (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue An A ...
- pat04-树4. Root of AVL Tree (25)
04-树4. Root of AVL Tree (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue An A ...
随机推荐
- SQLi-Labs之1~6关 - 常规注入与盲注
年初五 财神入 第一关 联合注入 1.准备 2.加'截断 3.order by 判断查询列数 4.同上 5.联合查询判断字段位置 6.查数据库名 7.1 查表名 7.2 查列名 8.查数据 第二关 不 ...
- nsq 初学使用日记
win下更加直观一些,所以不使用liunx 第一步下载 nsq 下载地址 https://github.com/nsqio/nsq.git 使用git clone或者go get 下载下来 第二部 编 ...
- RTOS文件系统对比:LittleFS Vs. SPIFFS
概述 在RTOS上免费的文件系统本身就不多,广泛使用且掉电安全的就更少了.本文选取当前RTOS上比较受欢迎的两个文件系统 SPIFFS 和 LittleFS 做全方位的对比,以便项目上评估在RTOS上 ...
- element中的树形组件,如何获取父级菜单的id
一般多选的树形组件,使用getCheckedNodes()方法只能获取到本级的菜单id,只有在子菜单全部选中的情况下才会选中上级.但我们想要不全选中子级的情况下也要获取它的上级,甚至上上级等,怎么办呢 ...
- 【Python】pyinstaller打包运行报错failed to execute script main
前言 最近用pyinstaller打包的时候一直报"failed to execute script main". 最终使用"pyinstaller --hidden-i ...
- javaScript 基础知识汇总(七)
1.数组 特点:数组是可以存储有序集合的对象. 声明: let arr = new Array(); let arr=[]; 大多数情况下我们使用第二种. let fruits = [" ...
- stm32的hall库新建模板编译错误: #error "Please select first the target STM32F1xx device used in your application (in stm32f1xx.h file)"的处理
在stm32f1xx.h file文件中找到如下代码: /* Uncomment the line below according to the target STM32L device used i ...
- java-FileUtils(读取、判断、获取)-(新手)
实例: lx1: import org.apache.commons.io.*; import java.io.File; import java.io.IOException; public cla ...
- Arch Linux安装配置-双系统(1)
Arch Linux启动盘准备: 在Windows下安装Win32 Disk Imager,打开页面,点击Download即可! 安装配置 1.选择我同意 2.选择安装位置路径 3.打勾,在桌面显示图 ...
- vscode如何配置debug,python正则表达式如何匹配括号,关于python如何导入自定义模块
关于vscode如何配置debug的问题: 1.下载安装好python,并且配置好 环境变量 2.https://www.cnblogs.com/asce/p/11600904.html 3.严格按照 ...