Kattis - Different Distances

Input
The input file contains up to 10001000 test cases,
each of which contains five real numbers, x1 y1 x2 y2 px1 y1 x2 y2 p,
each of which have at most 1010 digits past the decimal point.
All are in the range (0,100](0,100]. The last test case is followed by a line containing a single zero.
Output
For each test case output the pp-norm distance between the two points (x1,y1)(x1,y1) and (x2,y2)(x2,y2).
The answer should be accurate within 0.00010.0001 error.
| Sample Input 1 | Sample Output 1 |
|---|---|
1.0 1.0 2.0 2.0 2.0 |
1.4142135624 |
题意
给出x1,y1,x2,y2,p,按照上面最后一个给出来的公式算,水题,没坑
代码
#include<bits/stdc++.h>
using namespace std;
int main() {
double x1, y1, x2, y2, p, sum;
while(scanf("%lf", &x1) && x1 != 0.0) {
scanf("%lf%lf%lf%lf", &y1, &x2, &y2, &p);
sum = pow((pow(fabs(x1 - x2), p) + pow(fabs(y1 - y2), p)), 1.0 / p);
printf("%.10f\n", sum);
}
return ;
}
Kattis - Different Distances的更多相关文章
- Kattis - Biased Standings
Biased Standings Usually, results of competitions are based on the scores of participants. However, ...
- codeforces 803B Distances to Zero
Distances to Zero 题目链接:http://codeforces.com/problemset/problem/803/B 题目大意: 给一串数字,求每个数字到离他最近数字0的距离.. ...
- [Swift]LeetCode834. 树中距离之和 | Sum of Distances in Tree
An undirected, connected tree with N nodes labelled 0...N-1 and N-1 edges are given. The ith edge co ...
- Codechef Bear and Clique Distances
题目:Bear and Clique Distances 描述:共有N个点,前1—K个点任意两点之间有一条无向边,边的权值为X,再任意给M条边(u,v,w)(不重复),求任意一点到其余各点的最短路. ...
- It's a Mod, Mod, Mod, Mod World Kattis - itsamodmodmodmodworld (等差数列求和取模)
题目链接: D - It's a Mod, Mod, Mod, Mod World Kattis - itsamodmodmodmodworld 具体的每个参数的代表什么直接看题面就好了. AC代码: ...
- A - Piece of Cake Kattis - pieceofcake (数学)
题目链接: A - Piece of Cake Kattis - pieceofcake 题目大意:给你一个多边形,然后给你这个多边形的每个点的坐标,让你从这个n个点中选出k个点,问这个k个点形成的面 ...
- Subsequences in Substrings Kattis - subsequencesinsubstrings (暴力)
题目链接: Subsequences in Substrings Kattis - subsequencesinsubstrings 题目大意:给你字符串s和t.然后让你在s的所有连续子串中,找出这些 ...
- G - Intersecting Rectangles Kattis - intersectingrectangles (扫描线)(判断多个矩形相交)
题目链接: G - Intersecting Rectangles Kattis - intersectingrectangles 题目大意:给你n个矩形,每一个矩形给你这个矩形的左下角的坐标和右上角 ...
- E - Emptying the Baltic Kattis - emptyingbaltic (dijkstra堆优化)
题目链接: E - Emptying the Baltic Kattis - emptyingbaltic 题目大意:n*m的地图, 每个格子有一个海拔高度, 当海拔<0的时候有水. 现在在(x ...
随机推荐
- lucene_02_IKAnalyre
前言 在lucene中虽然已经提供了许多的分词器:StandardAnalyzer.CJKAnalyzer等,但在解析中文的时候都会把文中拆成一个个的单子. 毕竟老外不懂中文.这里介绍一个中文的分词器 ...
- Tkinter之输入框操作
昨天看好的,更新一下记录而已. #coding: utf8 from Tkinter import * def reg(): s1 = e1.get() s2 = e2.get() t1 = len( ...
- Docker入门介绍
Docker是一种虚拟化技术 刚開始看Docker,感觉非常抽象"An open platform for distributed applications for develo ...
- [Javascript Crocks] Safely Access Object Properties with `prop`
In this lesson, we’ll use a Maybe to safely operate on properties of an object that could be undefin ...
- T2: 一种能累积计算积分的EC2实例类型
假设您打算在AWS云端执行一个小型的 Web Server,或是一个小型的数据库,平时并没有大量的工作负载.在绝大多数时间里,您的实例并不须要消耗大量的CPU资源.可是,再不怎么受欢迎的博客也可能会有 ...
- GMGDC专訪戴亦斌:具体解释QAMAster全面測试服务6大功能
GMGDC专訪戴亦斌:具体解释QAMAster全面測试服务6大功能 2014/10/10 · Testin · 业界资讯 在9月24-25日第三届全球移动游戏开发人员大会上,Testin云測COO戴亦 ...
- 数据结构之---C语言实现共享栈
所谓共享栈是两个栈在一个顺序的存储空间中.两个栈的栈底各自是存储空间的首尾地址. 如图我们能够将两个栈构造成一个: 如图: 从这里也就能够分析出来,栈1为空时,就是top1等于-1时.而当top2等于 ...
- Oracle 数据块损坏与恢复具体解释
1.什么是块损坏: 所谓损坏的数据块,是指块没有採用可识别的 Oracle 格式,或者其内容在内部不一致. 通常情况下,损坏是由硬件故障或操作系统问题引起的.Oracle 数据库将损坏的块标识为&qu ...
- Centos7操作系统部署指南
一.硬件环境: Dell R620 二.软件环境: Centos6.4 X86_64 +KVM Windows7+vnc 三.安装说明 操作系统更新之迅速,让作为新手的系统运维人员有点措手不及,相对于 ...
- 【Codeforces 258D】 Count Good Substrings
[题目链接] http://codeforces.com/contest/451/problem/D [算法] 合并后的字符串一定是形如"ababa","babab&qu ...