111. Minimum Depth of Binary Tree

Easy

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

Note: A leaf is a node with no children.

Example:

Given binary tree [3,9,20,null,null,15,7],

    3
/ \
9 20
/ \
15 7

return its minimum depth = 2.

package leetcode.easy;

/**
* Definition for a binary tree node. public class TreeNode { int val; TreeNode
* left; TreeNode right; TreeNode(int x) { val = x; } }
*/
public class MinimumDepthOfBinaryTree {
public int minDepth(TreeNode root) {
if (null == root) {
return 0;
} else if (null == root.left) {
return 1 + minDepth(root.right);
} else if (null == root.right) {
return 1 + minDepth(root.left);
} else {
return 1 + Math.min(minDepth(root.left), minDepth(root.right));
}
} @org.junit.Test
public void test() {
TreeNode tn11 = new TreeNode(3);
TreeNode tn21 = new TreeNode(9);
TreeNode tn22 = new TreeNode(20);
TreeNode tn33 = new TreeNode(15);
TreeNode tn34 = new TreeNode(7);
tn11.left = tn21;
tn11.right = tn22;
tn21.left = null;
tn21.right = null;
tn22.left = tn33;
tn22.right = tn34;
tn33.left = null;
tn33.right = null;
tn34.left = null;
tn34.right = null;
System.out.println(minDepth(tn11));
}
}

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