poj 2585 Window Pains 解题报告
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 2027 | Accepted: 1025 |
Description
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When Boudreaux brings a window to the foreground, all of its squares come to the top, overlapping any squares it shares with other windows. For example, if window 1and then window 2 were brought to the foreground, the resulting representation would be:
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If window 4 were then brought to the foreground: |
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. . . and so on . . .
Unfortunately, Boudreaux's computer is very unreliable and crashes often. He could easily tell if a crash occurred by looking at the windows and seeing a graphical representation that should not occur if windows were being brought to the foreground correctly. And this is where you come in . . .
Input
A single data set has 3 components:
- Start line - A single line:
START - Screen Shot - Four lines that represent the current graphical representation of the windows on Boudreaux's screen. Each position in this 4 x 4 matrix will represent the current piece of window showing in each square. To make input easier, the list of numbers on each line will be delimited by a single space.
- End line - A single line:
END
After the last data set, there will be a single line:
ENDOFINPUT
Note that each piece of visible window will appear only in screen areas where the window could appear when brought to the front. For instance, a 1 can only appear in the top left quadrant.
Output
THESE WINDOWS ARE CLEAN
Otherwise, the output will be a single line with the statement:
THESE WINDOWS ARE BROKEN
Sample Input
START
1 2 3 3
4 5 6 6
7 8 9 9
7 8 9 9
END
START
1 1 3 3
4 1 3 3
7 7 9 9
7 7 9 9
END
ENDOFINPUT
Sample Output
THESE WINDOWS ARE CLEAN
THESE WINDOWS ARE BROKEN
Source
/*
Problem:poj 2585
OJ: POJ
User: S.B.S.
Time: 0 ms
Memory: 700 kb
Length: 1991 b
*/
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<queue>
#include<cstdlib>
#include<iomanip>
#include<cassert>
#include<climits>
#include<vector>
#include<list>
#include<map>
#define maxn 10001
#define F(i,j,k) for(int i=j;i<k;i++)
#define M(a,b) memset(a,b,sizeof(a))
#define FF(i,j,k) for(int i=j;i>=k;i--)
#define inf 0x7fffffff
#define maxm 2016
#define mod 1000000007
//#define LOCAL
using namespace std;
int read(){
int x=,f=;char ch=getchar();
while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}
while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}
return x*f;
}
int n,m;
int sc[][];
string cr[][];
bool vis[];
int in[];
bool g[][];
int t;
string s;
inline void init()
{
F(i,,)F(j,,) cr[i][j].erase();
F(k,,){
int i=(k-)/;
int j=(k-)%;
cr[i][j]+=char(k+'');
cr[i][j+]+=char(k+'');
cr[i+][j]+=char(k+'');
cr[i+][j+]+=char(k+'');
}
}
inline void input()
{
int i,j;
M(vis,);M(in,);M(g,);
t=;
int k;
F(i,,)F(j,,){
cin>>k;
sc[i][j]=k;
if(!vis[k]) t++;
vis[k]=true;
}
}
inline void build()
{
int a,b;
F(i,,)F(j,,)F(k,,cr[i][j].length())
{
if((!g[sc[i][j]][cr[i][j][k]-''])&&(sc[i][j]!=cr[i][j][k]-''))
{
g[sc[i][j]][cr[i][j][k]-'']=true;
in[cr[i][j][k]-'']++;
}
}
}
inline bool ok()
{
int i,j,k;
F(k,,t){
i=;
while(!vis[i]||(i<=&&in[i]>)) i++;
if(i>) return false;
vis[i]=false;
F(j,,){
if(vis[j]&&g[i][j]) in[j]--;
}
}
return true;
}
int main()
{
std::ios::sync_with_stdio(false);//cout<<setiosflags(ios::fixed)<<setprecision(1)<<y;
#ifdef LOCAL
freopen("data.in","r",stdin);
freopen("data.out","w",stdout);
#endif
init();
while(cin>>s)
{
if(s=="ENDOFINPUT") break;
input();
build();
if(ok()) cout<<"THESE WINDOWS ARE CLEAN"<<endl;
else cout<<"THESE WINDOWS ARE BROKEN"<<endl;
cin>>s;
}
return ;
}
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