YTU 2902: H-Sum 3s

2902: H-Sum 3s

时间限制: 1 Sec  内存限制: 128 MB

提交: 139  解决: 28

题目描述

You are given a number sequence a1,a2,a3...,an , your task is to find if there is a pair of interger (i,j) that ai+a(i+1)+..+aj equals to 0 and i<=j;

输入

Input consists of multiple test cases. For each case, the first line of input contains an integer n, the next line follows n integers. (n>=1 && n<=10^5 |ai|<=10^4)

输出

For each case, if there is at least one pair of integer (i,j) meet the requirement, print “YES”, otherwise print “NO” .

样例输入

51 2 3 4 553 4 -2 -3 1

样例输出

NOYES

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#include <iostream>
#include <algorithm>
using namespace std;
int main()
{
    int N;
    while (cin>>N)
    {
        int i,k=0,a[100000],s[100000];
        cin>>a[0];
        s[0]=a[0];
        if (a[0]==0)
            k=1;
        for (i=1; i<N; i++)
        {
            cin>>a[i];
            s[i]=s[i-1]+a[i];
            if (a[i]==0||s[i]==0)
                k=1;
        }
        if (k==0)
        {
            sort(s,s+N);
            for (i=0; i<N-1; i++)
                if (s[i]==s[i+1])
                {
                    k=1;
                    break;
                }
        }
        if (k==1)
            cout<<"YES"<<endl;
        else
            cout<<"NO"<<endl;

    }
    return 0;
}