P4525 【模板】自适应辛普森法1

P4525 【模板】自适应辛普森法1

 #include <bits/stdc++.h>
 using namespace std;
 const double eps = 1e-;
 double a, b, c, d, l, r;
 inline double f(double x) {
     return (c*x+d)/(a*x+b);
 }
 inline double simpson(double l, double r) {
     double mid = (l+r)/;
     return (f(l)+*f(mid)+f(r))*(r-l)/;
 }
 inline double asr(double l, double r, double eps, double ans) {
     double mid = (l+r)/;
     double ll = simpson(l,mid), rr = simpson(mid,r);
     if (fabs(ll+rr-ans) <= *eps) return ll+rr+(ll+rr-ans)/;
     return asr(l,mid,eps/,ll)+asr(mid,r,eps/,rr);
 }
 inline double asr(double l, double r, double eps) {
     return asr(l,r,eps,simpson(l,r));
 }
 int main() {
     scanf("%lf%lf%lf%lf%lf%lf",&a,&b,&c,&d,&l,&r);
     printf("%.6f",asr(l,r,eps));
     return ;
 }