原题:Populating Next Right Pointers in Each Node

简单的链表二叉树增加Next节点信息,没什么坑。不过还是WA了两次,还是有点菜,继续做,另外leetcode一共150题,考虑两周做完吧,要加速了。

注意:看清楚左右和递归,像标题说的,Go_deep吧。

/**
* Definition for binary tree with next pointer.
* struct TreeLinkNode {
* int val;
* TreeLinkNode *left, *right, *next;
* TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {}
* };
*/
class Solution {
public:
void connect(TreeLinkNode *root) {
if (root == NULL) return; if (root->left != NULL)
{
root->left->next = root->right; TreeLinkNode *go_deep_left = root->left->right;
TreeLinkNode *go_deep_right = (root->right != NULL)?(root->right->left):NULL; while (go_deep_left != NULL && go_deep_right != NULL)
{
go_deep_left->next = go_deep_right; go_deep_left = go_deep_left->right;
go_deep_right = go_deep_right->left;
}
} connect(root->right);
connect(root->left);
}
};

3月3日[Go_deep]Populating Next Right Pointers in Each Node的更多相关文章

  1. 【LeetCode】117. Populating Next Right Pointers in Each Node II 解题报告(Python)

    [LeetCode]117. Populating Next Right Pointers in Each Node II 解题报告(Python) 标签: LeetCode 题目地址:https:/ ...

  2. Leetcode 笔记 117 - Populating Next Right Pointers in Each Node II

    题目链接:Populating Next Right Pointers in Each Node II | LeetCode OJ Follow up for problem "Popula ...

  3. Leetcode 笔记 116 - Populating Next Right Pointers in Each Node

    题目链接:Populating Next Right Pointers in Each Node | LeetCode OJ Given a binary tree struct TreeLinkNo ...

  4. [LeetCode] Populating Next Right Pointers in Each Node II 每个节点的右向指针之二

    Follow up for problem "Populating Next Right Pointers in Each Node". What if the given tre ...

  5. [LeetCode] Populating Next Right Pointers in Each Node 每个节点的右向指针

    Given a binary tree struct TreeLinkNode { TreeLinkNode *left; TreeLinkNode *right; TreeLinkNode *nex ...

  6. LEETCODE —— Populating Next Right Pointers in Each Node

    Populating Next Right Pointers in Each Node Given a binary tree struct TreeLinkNode { TreeLinkNode * ...

  7. LeetCode - Populating Next Right Pointers in Each Node II

    题目: Follow up for problem "Populating Next Right Pointers in Each Node". What if the given ...

  8. 【leetcode】Populating Next Right Pointers in Each Node II

    Populating Next Right Pointers in Each Node II Follow up for problem "Populating Next Right Poi ...

  9. 【leetcode】Populating Next Right Pointers in Each Node

    Populating Next Right Pointers in Each Node Given a binary tree struct TreeLinkNode { TreeLinkNode * ...

随机推荐

  1. Cts框架解析(12)-ITargetPreparer

    測试开启前的设备系统准备工作. 接口 /* * Copyright (C) 2010 The Android Open Source Project * * Licensed under the Ap ...

  2. Android提高21篇之一:MediaPlayer

    本文介绍MediaPlayer的使用.MediaPlayer可以播放音频和视频,另外也可以通过VideoView来播放视频,虽然VideoView比MediaPlayer简单易用,但定制性不如用Med ...

  3. socket通信简单介绍

    “一切皆Socket!” 话虽些许夸张,可是事实也是,如今的网络编程差点儿都是用的socket. ——有感于实际编程和开源项目研究. 我们深谙信息交流的价值,那网络中进程之间怎样通信,如我们每天打开浏 ...

  4. 统计0到n之间1的个数

    问题描写叙述 给定一个十进制整数N,求出从1到N的全部整数中出现"1"的个数. 比如:N=2时 1,2出现了1个 "1" . N=12时 1,2,3,4,5,6 ...

  5. xtrabackup原理0

  6. [Effective C++ --033]避免遮掩继承而来的名称

    这一章一直在想怎么写,因为比较基础,很容易理解,就按照需要来写吧. 假设我们有这样一个类: class Base { private: int x; public: ; virtual void mf ...

  7. 关于try...catch...finally中return的疑惑

    原文:http://www.cnblogs.com/and_he/archive/2012/04/17/2453703.html 关于try...catch...finally里面的return一直是 ...

  8. 我的第一款Cocos2d 游戏小狗快跑基本完成

  9. df 和 du 命令详解

    df命令详细用法 a:显示全部的档案系统和各分割区的磁盘使用情形 i:显示i -nodes的使用量 k:大小用k来表示 (默认值) t:显示某一个档案系统的所有分割区磁盘使用量 x:显示不是某一个档案 ...

  10. CF Amr and Music (贪心)

    Amr and Music time limit per test 1 second memory limit per test 256 megabytes input standard input ...