Description

Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).

The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.

The picture illustrates the first and the second samples.

Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!

Input

The only line contains three integers nm and k (1 ≤ n, m ≤ 10 000, 1 ≤ k ≤ 2nm) — the number of lanes, the number of desks in each lane and the number of Santa Claus' place.

Output

Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.

Examples
input
4 3 9
output
2 2 L
input
4 3 24
output
4 3 R
input
2 4 4
output
1 2 R
Note

The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.

In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.

题意:告诉我们座位的排序方式,让我们找出k号是几行几列,是左还是右

解法:数学计算(奇数偶数为L,R,列可以通过k/x求出,行这里我先计算(y-1)有多少个数字,再调整)

#include<bits/stdc++.h>
using namespace std;
#define ll long long
int n,m,k;
int a[];
int x,y;
int t;
int main()
{
cin>>n>>m>>k;
x=m*;
if(k%x==)
{
y=k/x;
}
else
{
y=k/x+;
}
if(k%==)
{
if(y==)
{
cout<<y<<" "<<(k+)/<<" "<<"R"<<endl;
}
else
{
cout<<y<<" "<<(k-(y-)**m+)/<<" "<<"R"<<endl;
}
}
else
{
if(y==)
{
cout<<y<<" "<<(k+)/<<" "<<"L"<<endl;
}
else
{
cout<<y<<" "<<(k-(y-)**m+)/<<" "<<"L"<<endl;
}
}
return ;
}

Codeforces Round #389 (Div. 2, Rated, Based on Technocup 2017 - Elimination Round 3) A的更多相关文章

  1. Codeforces Round #389 (Div. 2, Rated, Based on Technocup 2017 - Elimination Round 3) C

    Description Santa Claus has Robot which lives on the infinite grid and can move along its lines. He ...

  2. Codeforces Round #389 (Div. 2, Rated, Based on Technocup 2017 - Elimination Round 3) B

    Description Santa Claus decided to disassemble his keyboard to clean it. After he returned all the k ...

  3. Codeforces Round #389 (Div. 2, Rated, Based on Technocup 2017 - Elimination Round 3) D. Santa Claus and a Palindrome STL

    D. Santa Claus and a Palindrome time limit per test 2 seconds memory limit per test 256 megabytes in ...

  4. Codeforces Round #389 (Div. 2, Rated, Based on Technocup 2017 - Elimination Round 3) E. Santa Claus and Tangerines

    E. Santa Claus and Tangerines time limit per test 2 seconds memory limit per test 256 megabytes inpu ...

  5. Codeforces Round #389 (Div. 2, Rated, Based on Technocup 2017 - Elimination Round 3) 圣诞之夜!

    A. Santa Claus and a Place in a Class 模拟题.(0:12) 题意:n列桌子,每列m张桌子,每张桌子一分为2,具体格式看题面描述.给出n,m及k.求编号为k的桌子在 ...

  6. Codeforces Round #380 (Div. 1, Rated, Based on Technocup 2017 - Elimination Round 2)

    http://codeforces.com/contest/737 A: 题目大意: 有n辆车,每辆车有一个价钱ci和油箱容量vi.在x轴上,起点为0,终点为s,中途有k个加油站,坐标分别是pi,到每 ...

  7. codeforces Codeforces Round #380 (Div. 1, Rated, Based on Technocup 2017 - Elimination Round 2)// 二分的题目硬生生想出来ON的算法

    A. Road to Cinema 很明显满足二分性质的题目. 题意:某人在起点处,到终点的距离为s. 汽车租赁公司提供n中车型,每种车型有属性ci(租车费用),vi(油箱容量). 车子有两种前进方式 ...

  8. Codeforces Round #380 (Div. 2, Rated, Based on Technocup 2017 - Elimination Round 2) E. Subordinates 贪心

    E. Subordinates time limit per test 1 second memory limit per test 256 megabytes input standard inpu ...

  9. Codeforces Round #380 (Div. 2, Rated, Based on Technocup 2017 - Elimination Round 2) D. Sea Battle 模拟

    D. Sea Battle time limit per test 1 second memory limit per test 256 megabytes input standard input ...

随机推荐

  1. RelativeLayout中实现控件平分屏幕

    <RelativeLayout android:layout_width="fill_parent" android:layout_height="wrap_con ...

  2. vs2015企业版和专业版秘钥

    专业版:HMGNV-WCYXV-X7G9W-YCX63-B98R2企业版:HM6NR-QXX7C-DFW2Y-8B82K-WTYJV 来自http://www.cnblogs.com/xuhongfe ...

  3. 控制反转IOC的依赖注入方式

    引言: 项目中遇到关于IOC的一些内容,因为和正常的逻辑代码比较起来,IOC有点反常.因此本文记录IOC的一些基础知识,并附有相应的简单实例,而在实际项目中再复杂的应用也只是在基本应用的基础上扩展而来 ...

  4. android 中获取当前焦点所在屏幕中的位置 view.getLocationOnScreen(location)

    final int[] location = new int[2]; view.getLocationOnScreen(location); final int[] location = new in ...

  5. Git过滤文件和文夹

    今天是2016年10月份的最后一天,感觉时间过得真的是飞快呢,此刻天下着小雨,天气灰蒙如天每个人的心情一样.在此把这个月的项目上传到git上,就需要过滤一些项目自动生成的不必要的文件,如:bin,ob ...

  6. ios 控件显示不出来的几个可能

  7. 设计模式学习笔记c++版——单例模式

    特别注意单例模式c++实现在main.cpp中引用的时候要去申明下: Singleton * Singleton::m_Instance = NULL; //定义性声明 不然会报错:无法解析的外部符号 ...

  8. 第十二章Fundamental Data Types 基本数据类型

    目录: 12.1 数值概论 12.2整数 12.3浮点数 12.4 字符和字符串 12.5布尔变量 12.6枚举类型 12.7具名常量 12.8数组 12.9创建你自己的类型 12.1   数值概论 ...

  9. GetLastError()函数返回值及含义

    GetLastError返回的值通过在api函数中调用SetLastError或SetLastErrorEx设置.函数并无必要设置上一次错误信息,所以即使一次GetLastError调用返回的是零值, ...

  10. zjuoj 3780 Paint the Grid Again

    http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3780 Paint the Grid Again Time Limit: 2 ...