You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

解题思路:

递归会导致超时,用动态规划即可,JAVA实现如下;

    public int climbStairs(int n) {
if(n==1)
return 1;
else if(n==2)
return 2;
int[] v=new int[n];
v[0]=1;
v[1]=2;
for(int i=2;i<v.length;i++)
v[i]=v[i-1]+v[i-2];
return v[n-1];
}

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