迭代加深搜索,从小到大枚举桶数的上限maxd:对每个maxd,枚举每个组合,判断是否能够倒出q;直到得到answer。判断的部分就用dp(完全背包)。

-------------------------------------------------------------------------

#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
#include<vector>
#include<cctype>
#define rep(i,r) for(int i=0;i<r;i++)
#define clr(x,c) memset(x,c,sizeof(x))
#define Rep(i,l,r) for(int i=l;i<r;i++)
using namespace std;
const int maxn=100+5,maxq=20000+5;
int q,n;
int d[maxq];
bool ok[maxn];
bool pd=0;
int maxd=0;
vector<int> use;
vector<int> v;
void read(int &n) {
char c=getchar();
while(!isdigit(c)) c=getchar();
n=0;
while(isdigit(c)) {
n=n*10+c-'0';
c=getchar();
}
}
int jud() {
clr(d,0); d[0]=1;
Rep(i,use[0],q+1)
   rep(j,use.size()) if(i>=use[j]) d[i]|=d[i-use[j]];
if(d[q]) {
cout<<maxd;
rep(i,use.size()) printf(" %d",use[i]);
printf("\n");
   return 1;
}
return 0;
}
int dfs(int i) {
if(pd) return 0;
if(use.size()==maxd) {
if(jud()) pd=1;
return 0;
}
if(v.size()-i-1+use.size()<maxd) return 0;
Rep(j,i+1,v.size()) {
use.push_back(v[j]);
dfs(j);
use.pop_back();
}
return 0;
}
int main()
{
freopen("milk4.in","r",stdin);
freopen("milk4.out","w",stdout);
clr(ok,0);
read(q); read(n);
rep(i,n) {
int t;
read(t);
rep(j,v.size()) if(v[j]%t==0) t=0;
if(t) v.push_back(t);
}
sort(v.begin(),v.end());
while(!pd) {
use.clear();
maxd++;
dfs(-1);
}
return 0;
}

-------------------------------------------------------------------------

Milk Measuring
Hal Burch

Farmer John must measure Q (1 <= Q <= 20,000) quarts of his finest milk and deliver it in one big bottle to a customer. He fills that bottle with exactly the number of quarts that the customer orders.

Farmer John has always been frugal. He is at the cow hardware store where he must purchase a set of pails with which to measure out Q quarts of milk from his giant milk tank. Since the pails each cost the same amount, your task is to figure out a minimal set of pails Farmer John can purchase in order to fill a bottle with exactly Q quarts of milk. Additionally, since Farmer John has to carry the pails home, given two minimal sets of pails he should choose the "smaller" one as follows: Sort the sets in ascending order. Compare the first pail in each set and choose the set with the smallest pail. If the first pails match, compare the second pails and choose from among those, else continue until the two sets differ. Thus the set {3, 5, 7, 100} should be chosen over {3, 6, 7, 8}.

To measure out milk, FJ may completely fill a pail from the tank and pour it into the bottle. He can never remove milk from the bottle or pour milk anywhere except into the bottle. With a one-quart pail, FJ would need only one pail to create any number of quarts in a bottle. Other pail combinations are not so convenient.

Determine the optimally small number of pails to purchase, given the guarantee that at least one solution is possible for all contest input data.

PROGRAM NAME: milk4

INPUT FORMAT

Line 1: The single integer Q
Line 2: A single integer P (1 <= P <= 100) which is the number of pails in the store
Lines 3..P+2: Each line contains a single integer pail_value (1 <= pail_value <= 10000), the number of quarts a pail holds

SAMPLE INPUT (file milk4.in)

16 3 3 5 7 

OUTPUT FORMAT

The output is a single line of space separated integers that contains:

  • the minimum number of pails required to measure out the desired number of quarts, followed by:
  • a sorted list (from smallest to largest) of the capacity of each of the required pails

SAMPLE OUTPUT (file milk4.out)

2 3 5

USACO Section 5.3 Milk Measuring (IDDFS+dp)的更多相关文章

  1. USACO 5.3 Milk Measuring

    Milk MeasuringHal Burch Farmer John must measure Q (1 <= Q <= 20,000) quarts of his finest mil ...

  2. USACO Section 5.3 Big Barn(dp)

    USACO前面好像有类似的题目..dp(i,j)=min(dp(i+1,j),dp(i+1,j+1),dp(i,j+1))+1  (坐标(i,j)处无tree;有tree自然dp(i,j)=0) .d ...

  3. 洛谷 P2744 [USACO5.3]量取牛奶Milk Measuring

    P2744 [USACO5.3]量取牛奶Milk Measuring 题目描述 农夫约翰要量取 Q(1 <= Q <= 20,000)夸脱(夸脱,quarts,容积单位——译者注) 他的最 ...

  4. luogu P2744 [USACO5.3]量取牛奶Milk Measuring

    题目描述 农夫约翰要量取 Q(1 <= Q <= 20,000)夸脱(夸脱,quarts,容积单位——译者注) 他的最好的牛奶,并把它装入一个大瓶子中卖出.消费者要多少,他就给多少,从不有 ...

  5. [USACO Section 5.3]量取牛奶 Milk Measuring (动态规划,背包$dp$)

    题目链接 Solution 完全背包 \(dp\) , 同时再加一个数组 \(v[i][j]\) 记录当总和为\(j\) 时第 \(i\) 种物品是否被选. 为保证从小到大和字典序,先将瓶子按大小排序 ...

  6. USACO Section 1.3 Mixing Milk 解题报告

    题目 题目描述 Merry Milk Makers 公司的业务是销售牛奶.它从农夫那里收购N单位的牛奶,然后销售出去.现在有M个农夫,每个农夫都存有一定量的牛奶,而且每个农夫都会有自己的定价.假设所有 ...

  7. USACO Section 1.4 Mother's Milk 解题报告

    题目 题目描述 有三个牛奶桶,三个桶的容积分别是A,B,C,最小为1,最大为20.刚开始只有第三个桶里面装满了牛奶,其余两个桶都是空的.我们现在可以将第三个桶中的牛奶往其他两个桶里面倒一些牛奶,然后还 ...

  8. [USACO5.3]量取牛奶Milk Measuring

    https://daniu.luogu.org/problemnew/show/P2744 滚动数组压去第一维:前i种木桶 f[j] 量取体积j最少需要几种木桶 g[j]  体积j的最优解是否使用了第 ...

  9. 【USACO 2.3】Money Systems(dp)

    v种货币,求有多少种组成和为n. dp[i][j]表示前i种货币价格为j有多少种方案,dp[i][j]+=dp[i-1][j-c]. http://train.usaco.org/usacoprob2 ...

随机推荐

  1. centos扩容(pv,vg,lv)

    preFace: (应用场景需求分析)

  2. python-大话装饰器

    装饰器 装饰器是个什么玩意呢?是个会了不难,装逼神器.但是如果不了解理解起来还是很抽象,让我们试试这个装逼神器吧! 1.什么是装饰器 装饰器是一个很著名的设计模式,经常被用于有切面需求的场景,较为经典 ...

  3. python访问cloudstack的api接口

    1.CloudStack API 如同 AWS API 一样,CloudStack API 也是基于 Web Service,可以使用任何一种支持 HTTP 调用的语言(例如 Java,python, ...

  4. hive集群安装配置

    hive 是JAVA写的的一个数据仓库,依赖hadoop.没有安装hadoop的,请参考http://blog.csdn.net/lovemelovemycode/article/details/91 ...

  5. 音乐ID3 中 专辑封面解析(APIC帧)

    ID3V2 中 APIC 帧标识 专辑封面.前几天 百度 谷歌 都没有找到具体的说明.有点小伤人. 最好参考  Android 中的 id3.cpp 以及一个java 开源 id3 库.找到这里的规格 ...

  6. 一步一步学android之布局管理器——RelativeLayout

    今天开始学习RelativeLayout(相对布局),相对布局在平时布局的时候用的较多,因为Android适配方面的原因.相对布局可以控制组件摆放的位置(放在任一组件的上下左右等位置),下面来看看类的 ...

  7. python手记(36)

    #!/usr/bin/env python #-*- coding: utf-8 -*- #code:myhaspl@qq.com import cv2 import numpy as np fn=& ...

  8. asp.net弹出多个模态窗口

    asp.net中无限制弹出模态窗口 特点: 1.       可以在模态窗口上再弹出模态窗口,不限制次数 2.       弹出窗口的支持拖放,及调整大小 3.       弹出窗口关闭后可以动态控制 ...

  9. HTTP的报文格式解析

    一.概述 http报文是面向文本的,报文中每一个字段都是一些ASCII码串,各个字段的长度是不确定的.http有两类报文:请求报文  响应报文 二.请求报文 一个http请求报文由 请求行(reque ...

  10. JavaScript之面向对象的概念,对象属性和对象属性的特性简介

    一.大家都知道,面向对象语言有一个标志,那就是他们都有类的概念,通过类我们可以创建任意多个具有相同属性和方法的对象.但ECMAScript(指定JavaScript标准的机构,也就是说JavaScri ...