Linq语法
希望能帮助一些linq新手。
开门见山
读这篇文章之前,我先说下,每一种搜索结果集,我都以三种方式变现出来,为啦更好的理解,希望不要嫌我啰嗦。
1.简单的linq语法

//1
var ss = from r in db.Am_recProScheme
select r;
//2
var ss1 = db.Am_recProScheme;
//3
string sssql = "select * from Am_recProScheme";

2.带where的查询

//1
var ss = from r in db.Am_recProScheme
where r.rpId > 10
select r;
//2
var ss1 = db.Am_recProScheme.Where(p => p.rpId > 10);
//3
string sssql = "select * from Am_recProScheme where rpid>10";

3.简单的函数计算(count,min,max,sum)

//1
////获取最大的rpId
//var ss = (from r in db.Am_recProScheme
// select r).Max(p => p.rpId);
////获取最小的rpId
//var ss = (from r in db.Am_recProScheme
// select r).Min(p => p.rpId);
//获取结果集的总数
//var ss = (from r in db.Am_recProScheme
// select r).Count();
//获取rpId的和
var ss = (from r in db.Am_recProScheme
select r).Sum(p => p.rpId); //2
//var ss1 = db.Am_recProScheme.Max(p=>p.rpId);
//var ss1 = db.Am_recProScheme.Min(p => p.rpId);
//var ss1 = db.Am_recProScheme.Count() ;
var ss1 = db.Am_recProScheme.Sum(p => p.rpId);
Response.Write(ss); //3
string sssql = "select max(rpId) from Am_recProScheme";
sssql = "select min(rpId) from Am_recProScheme";
sssql = "select count(1) from Am_recProScheme";
sssql = "select sum(rpId) from Am_recProScheme";

4.排序order by desc/asc

var ss = from r in db.Am_recProScheme
where r.rpId > 10
orderby r.rpId descending //倒序
// orderby r.rpId ascending //正序
select r; //正序
var ss1 = db.Am_recProScheme.OrderBy(p => p.rpId).Where(p => p.rpId > 10).ToList();
//倒序
var ss2 = db.Am_recProScheme.OrderByDescending(p => p.rpId).Where(p => p.rpId > 10).ToList(); string sssql = "select * from Am_recProScheme where rpid>10 order by rpId [desc|asc]";

5.top(1)

//如果取最后一个可以按倒叙排列再取值
var ss = (from r in db.Am_recProScheme
select r).FirstOrDefault(); //()linq to ef 好像不支持 Last()
var ss1 = db.Am_recProScheme.FirstOrDefault();
//var ss1 = db.Am_recProScheme.First(); string sssql = "select top(1) * from Am_recProScheme";

6.跳过前面多少条数据取余下的数据

//1
var ss = (from r in db.Am_recProScheme
orderby r.rpId descending
select r).Skip(10); //跳过前10条数据,取10条之后的所有数据
//2
var ss1 = db.Am_recProScheme.OrderByDescending(p => p.rpId).Skip(10).ToList();
//3
string sssql = "select * from (select ROW_NUMBER()over(order by rpId desc) as rowNum, * from [Am_recProScheme]) as t where rowNum>10";

7.分页数据查询

//1
var ss = (from r in db.Am_recProScheme
where r.rpId > 10
orderby r.rpId descending
select r).Skip(10).Take(10); //取第11条到第20条数据 //2 Take(10): 数据从开始获取,获取指定数量(10)的连续数据
var ss1 = db.Am_recProScheme.OrderByDescending(p => p.rpId).Where(p => p.rpId > 10).Skip(10).Take(10).ToList();
//3
string sssql = "select * from (select ROW_NUMBER()over(order by rpId desc) as rowNum, * from [Am_recProScheme]) as t where rowNum>10 and rowNum<=20";

8.包含,类似like '%%'

//1
var ss = from r in db.Am_recProScheme
where r.SortsText.Contains("张")
select r;
//2
var ss1 = db.Am_recProScheme.Where(p => p.SortsText.Contains("张")).ToList();
//3
string sssql = "select * from Am_recProScheme where SortsText like '%张%'";

9.分组group by

//1
var ss = from r in db.Am_recProScheme
orderby r.rpId descending
group r by r.recType into n
select new
{
n.Key, //这个Key是recType
rpId = n.Sum(r => r.rpId), //组内rpId之和
MaxRpId = n.Max(r => r.rpId),//组内最大rpId
MinRpId = n.Min(r => r.rpId), //组内最小rpId
};
foreach (var t in ss)
{
Response.Write(t.Key + "--" + t.rpId + "--" + t.MaxRpId + "--" + t.MinRpId);
}
//2
var ss1 = from r in db.Am_recProScheme
orderby r.rpId descending
group r by r.recType into n
select n;
foreach (var t in ss1)
{
Response.Write(t.Key + "--" + t.Min(p => p.rpId));
}
//3
var ss2 = db.Am_recProScheme.GroupBy(p => p.recType);
foreach (var t in ss2)
{
Response.Write(t.Key + "--" + t.Min(p => p.rpId));
}
//4
string sssql = "select recType,min(rpId),max(rpId),sum(rpId) from Am_recProScheme group by recType";

10.连接查询

//1
var ss = from r in db.Am_recProScheme
join w in db.Am_Test_Result on r.rpId equals w.rsId
orderby r.rpId descending
select r;
//2
var ss1 = db.Am_recProScheme.Join(db.Am_Test_Result, p => p.rpId, r => r.rsId, (p, r) => p).OrderByDescending(p => p.rpId).ToList();
//3
string sssql = "select r.* from [Am_recProScheme] as r inner join [dbo].[Am_Test_Result] as t on r.[rpId] = t.[rsId] order by r.[rpId] desc";

11.sql中的In

//1
var ss = from p in db.Am_recProScheme
where (new int?[] { 24, 25,26 }).Contains(p.rpId)
select p;
foreach (var p in ss)
{
Response.Write(p.Sorts);
}
//2
string st = "select * from Am_recProScheme where rpId in(24,25,26)";

如果你是linq新手,建议这十个常用的查询标记学习,再加上视图,基本上就能解决大部分的查询问题啦。
转载:http://www.cnblogs.com/knowledgesea/p/3897665.html
Linq语法的更多相关文章
- Linq语法详细
闲言碎语 近期比较忙,但还是想写点什么,就分享一些基础的知识给大家看吧,希望能帮助一些linq新手,如果有其它疑问,可以进右上角群,进行交流探讨,谢谢. 开门见山 读这篇文章之前,我先说下,每一种搜索 ...
- Linq语法详细(转)
原文地址:http://www.cnblogs.com/knowledgesea/p/3897665.html 开门见山 读这篇文章之前,我先说下,每一种搜索结果集,我都以三种方式变现出来,为啦更好的 ...
- Linq To Sql中实现Left Join与Inner Join使用Linq语法与lambda表达式
当前有两个表,sgroup与sgroupuser,两者通过gKey关联,而sgroup表记录的是组,而sgroupuser记录是组中的用户,因此在sgroupuser中不一定有数据.需要使用Left ...
- Lamda和Linq语法对比详细
本人转载:http://www.cnblogs.com/knowledgesea/p/3897665.html 闲言碎语 近期比较忙,但还是想写点什么,就分享一些基础的知识给大家看吧,希望能帮助一些l ...
- Linq 语法举例
1.简单的linq语法 //1 var ss = from r in db.Am_recProScheme select r; //2 var ss1 = db.Am_recProScheme; // ...
- LinQ 语法基础
LINQ (Language-Integrated Query,语言集成查询). LINQ to Objects.LINQ to SQL.LINQ to DataSet和LINQ to XML,它们分 ...
- Linq语法常见普通语法
闲言碎语 近期比较忙,但还是想写点什么,就分享一些基础的知识给大家看吧,希望能帮助一些linq新手,如果有其它疑问,可以进右上角群,进行交流探讨,谢谢. 开门见山 读这篇文章之前,我先说下,每一种搜索 ...
- C# LINQ语法详解
1.简单的linq语法 var ss = from r in db.Am_recProScheme select r; var ss1 = db.Am_recProScheme; string sss ...
- LINQ语法类似于SQL的语法
LINQ语法类似于SQL的语法如下, Models.BookStoreEntities 是从添加新建项中的数据--->ADO.NET实体数据模型--->从数据库生成--->使用5.0 ...
随机推荐
- 转载-smarty教程(基本语法)
转自:http://hi.baidu.com/qxxgvpdtzhbckpr/item/681049160d7be60db98a1aec 1.smarty的配置 首先,使用smarty第一件 ...
- Linux下简单的socket通信实例
Linux下简单的socket通信实例 If you spend too much time thinking about a thing, you’ll never get it done. —Br ...
- 【CSS】Beginner5:Margins&Padding
1.Properties for spacing-out elements 外边距:A margin is the space space outside something 内边距:padding ...
- nyoj 84阶乘后0的个数
描述 计算n!的十进制表示最后有多少个0 输入 第一行输入一个整数N表示测试数据的组数(1<=N<=100)每组测试数据占一行,都只有一个整数M(0<=M<=10000000) ...
- JDK1.5新特性(四)……Autoboxing/Unboxing
援引 Autoboxing/Unboxing - This facility eliminates the drudgery of manual conversion between primitiv ...
- bzoj 1226 [SDOI2009]学校食堂Dining(状压DP)
Description 小F 的学校在城市的一个偏僻角落,所有学生都只好在学校吃饭.学校有一个食堂,虽然简陋,但食堂大厨总能做出让同学们满意的菜肴.当然,不同的人口味也不一定相同,但每个人的口味都可以 ...
- ACM2028
Lowest Common Multiple Plus Problem Description 求n个数的最小公倍数. input 输入包含多个测试实例,每个测试实例的开始是一个正整数n,然后是n ...
- https原理:证书传递、验证和数据加密、解密过程解析
写的太好了,就是我一直想找的内容,看了这个对https立马明白多了 http://www.cnblogs.com/zhuqil/archive/2012/07/23/2604572.html 我们都知 ...
- hdu 2102 A计划(优先队列+dfs)
改了好久,上午来实验室打出来了,运行就是不对,一直找啊找!还是没找到,最后突然停电了,打好的代码还没保存呢! 刚才来的时候又重新打了一遍!!!结果一个小小的错误wrong了好久!!! 在dfs值返回时 ...
- (二)如何在.net中使用Redis
Step1:使用NuGet工具安装Redis C# API,这里有多个API我们可以使用其中一个: