Source:

PAT A1115 Counting Nodes in a BST (30 分)

Description:

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

  • The left subtree of a node contains only nodes with keys less than or equal to the node's key.
  • The right subtree of a node contains only nodes with keys greater than the node's key.
  • Both the left and right subtrees must also be binary search trees.

Insert a sequence of numbers into an initially empty binary search tree. Then you are supposed to count the total number of nodes in the lowest 2 levels of the resulting tree.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤) which is the size of the input sequence. Then given in the next line are the N integers in [which are supposed to be inserted into an initially empty binary search tree.

Output Specification:

For each case, print in one line the numbers of nodes in the lowest 2 levels of the resulting tree in the format:

n1 + n2 = n

where n1 is the number of nodes in the lowest level, n2 is that of the level above, and n is the sum.

Sample Input:

9
25 30 42 16 20 20 35 -5 28

Sample Output:

2 + 4 = 6

Keys:

Attention:

  • BST定义有时候会不一样,等号跟左子树还是右子树要看清楚,注意审题

Code:

 /*
Data: 2019-06-26 15:55:13
Problem: PAT_A1115#Counting Nodes in a BST
AC: 17:15 题目大意:
BST定义:lchild <= root < rchild
根据插入序列建立BST树,统计最底层和次底层的结点数量 基本思路:
建树,记录结点层次,全局变量记录树的最大深度
更新最大深度的同时,统计底层和次底层的结点个数
*/
#include<cstdio>
int deep=,n1=,n2=;
struct node
{
int data;
node *lchild,*rchild;
}; void Insert(node *&root, int x, int height)
{
if(root == NULL)
{
if(deep == height)
n1++;
else if(deep == height+)
n2++;
else if(deep == height-)
{
deep++;
n2 = n1;
n1 = ;
}
root = new node;
root->data = x;
root->lchild = root->rchild = NULL;
}
else if(x <= root->data)
Insert(root->lchild, x, height+);
else
Insert(root->rchild, x, height+);
} int main()
{
#ifdef ONLINE_JUDGE
#else
freopen("Test.txt", "r", stdin);
#endif // ONLINE_JUDGE int n,x;
scanf("%d", &n);
node *root = NULL;
for(int i=; i<n; i++)
{
scanf("%d", &x);
Insert(root,x,);
}
printf("%d + %d = %d", n1,n2,n1+n2); return ;
}

PAT_A1115#Counting Nodes in a BST的更多相关文章

  1. PAT1115:Counting Nodes in a BST

    1115. Counting Nodes in a BST (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Y ...

  2. PAT甲1115 Counting Nodes in a BST【dfs】

    1115 Counting Nodes in a BST (30 分) A Binary Search Tree (BST) is recursively defined as a binary tr ...

  3. 1115 Counting Nodes in a BST (30 分)

    1115 Counting Nodes in a BST (30 分) A Binary Search Tree (BST) is recursively defined as a binary tr ...

  4. [二叉查找树] 1115. Counting Nodes in a BST (30)

    1115. Counting Nodes in a BST (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Y ...

  5. PAT 1115 Counting Nodes in a BST[构建BST]

    1115 Counting Nodes in a BST(30 分) A Binary Search Tree (BST) is recursively defined as a binary tre ...

  6. A1115. Counting Nodes in a BST

    A Binary Search Tree (BST) is recursively defined as a binary tree which has the following propertie ...

  7. PAT A1115 Counting Nodes in a BST (30 分)——二叉搜索树,层序遍历或者dfs

    A Binary Search Tree (BST) is recursively defined as a binary tree which has the following propertie ...

  8. PAT 甲级 1115 Counting Nodes in a BST

    https://pintia.cn/problem-sets/994805342720868352/problems/994805355987451904 A Binary Search Tree ( ...

  9. 1115. Counting Nodes in a BST (30)

    A Binary Search Tree (BST) is recursively defined as a binary tree which has the following propertie ...

随机推荐

  1. JAVA模拟登录实例

    近期在做公司一个web项目.要求在我们的系统上,可以显示其它站点上的数据. 刚開始接到这个任务时,还在想.简单的非常.直接用UrlConection直接进入该网页,然后获取该网页的html,取到想要的 ...

  2. ajax——dom基础

    javascript中dom实现能够使我们在ajax中通过javascript代码对html和xml数据进行dom方式操作,从而做到页面的动态改动更新和数据的提取处理. dom概念 dom文档对象模型 ...

  3. HDU 4405 Aeroplane chess (概率DP求期望)

    题意:有一个n个点的飞行棋,问从0点掷骰子(1~6)走到n点须要步数的期望 当中有m个跳跃a,b表示走到a点能够直接跳到b点. dp[ i ]表示从i点走到n点的期望,在正常情况下i点能够到走到i+1 ...

  4. [Apple开发者帐户帮助]六、配置应用服务(1.1)Apple Pay:配置Apple Pay(iOS,watchOS)

    Apple Pay允许用户在您的应用中购买商品和服务.要将Apple Pay 权利添加到您的App ID,请先创建商家标识符,然后启用Apple Pay并创建付款处理证书. 或者,您可以使用Xcode ...

  5. Java.Cas4.0客户端接入配置

    1.本示例中使用cas4.0+cas-client-core3.4版本,ide则是myeclipse2014 blue版本,mvn使用3.9版本 2.注意事项:请先实现破解cas-client-cor ...

  6. 5.17领扣--Arrays.copyOf()方法

    ?? 给定一个整数数组 nums 和一个目标值 target,请你在该数组中找出和为目标值的那 两个 整数,并返回他们的数组下标. 你可以假设每种输入只会对应一个答案.但是,你不能重复利用这个数组中同 ...

  7. 5.14JDBC

    一.##JDBC 1. 概念:Java DataBase Connectivity  Java 数据库连接, Java语言操作数据库. JDBC本质:其实是官方(sun公司)定义的一套操作所有关系型数 ...

  8. JavaScript异步加载方案

    (1) defer,只支持IE defer属性的定义和用法(我摘自w3school网站) defer 属性规定是否对脚本执行进行延迟,直到页面加载为止. 有的 javascript 脚本 docume ...

  9. Android常见错误整理

    1.当我new class的时候,提示以下错误: Unable to parse template "Class" Error message: This template did ...

  10. windows和linux无法访问VMware中linux的tomcat主页问题

    1.一定确定自己的tomcat服务器是启动的.(为了确保保险可以在测试前重新shutdown,startup一次) 2.确定自己访问的ip地址和端口号是正确的 如果是VMware外部windows的话 ...