Container With Most Water（LintCode）

Container With Most Water

Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Example

Given [1,3,2], the max area of the container is 2.

Note

You may not slant the container.

从数组两头遍历，计算面积，然后从小的那一段a开始找到下一个比a大的元素。直到所有数组都被遍历。

 public class Solution {
     /**
      * @param heights: an array of integers
      * @return: an integer
      */
     public int maxArea(int[] heights) {
         int l = heights.length;
         if (l == 0) {
             return 0;
         }
         int max = -1;
         int i = 0;
         int j = l-1;
         while (i < j) {
             int v = (j - i) * Math.min(heights[i],heights[j]);
             if (max < v) {
                 max = v;
             }

             if(heights[i] > heights[j]){
                 int x = heights[j];
                 while (heights[j] <= x && i < j) j--;
             }else {
                 int x = heights[i];
                 while(heights[i] <= x && i < j) i++;
             }
         }
         return max;
     }
 }