Given a directed graph, design an algorithm to find out whether there is a route between two nodes.

Have you met this question in a real interview? Yes
Example
Given graph: A----->B----->C
\ |
\ |
\ |
\ v
->D----->E
for s = B and t = E, return true for s = D and t = C, return false

DFS:

 /**
* Definition for Directed graph.
* class DirectedGraphNode {
* int label;
* ArrayList<DirectedGraphNode> neighbors;
* DirectedGraphNode(int x) {
* label = x;
* neighbors = new ArrayList<DirectedGraphNode>();
* }
* };
*/
public class Solution {
/**
* @param graph: A list of Directed graph node
* @param s: the starting Directed graph node
* @param t: the terminal Directed graph node
* @return: a boolean value
*/
public boolean hasRoute(ArrayList<DirectedGraphNode> graph,
DirectedGraphNode s, DirectedGraphNode t) {
// write your code here
HashSet<DirectedGraphNode> visited = new HashSet<DirectedGraphNode>();
       visited.add(s);
return dfs(s, t, visited);
} public boolean dfs(DirectedGraphNode s, DirectedGraphNode t, HashSet<DirectedGraphNode> visited) {
if (s == t) return true;
for (DirectedGraphNode neighbor : s.neighbors) {
if (!visited.contains(neighbor)) {
visited.add(s);
if (dfs(neighbor, t, visited))
return true;
}
}
return false;
}
}

BFS:

 public class Solution {
/**
* @param graph: A list of Directed graph node
* @param s: the starting Directed graph node
* @param t: the terminal Directed graph node
* @return: a boolean value
*/
public boolean hasRoute(ArrayList<DirectedGraphNode> graph,
DirectedGraphNode s, DirectedGraphNode t) {
// write your code here
HashSet<DirectedGraphNode> visited = new HashSet<DirectedGraphNode>();
LinkedList<DirectedGraphNode> queue = new LinkedList<DirectedGraphNode>();
if (s == t) return true;
queue.offer(s);
visited.add(s);
while (!queue.isEmpty()) {
DirectedGraphNode cur = queue.poll();
for (DirectedGraphNode neighbor : cur.neighbors) {
if (neighbor == t) return true;
if (visited.contains(neighbor)) continue;
visited.add(neighbor);
queue.offer(neighbor);
}
}
return false;
}
}

Lintcode: Route Between Two Nodes in Graph的更多相关文章

  1. Route Between Two Nodes in Graph

    Given a directed graph, design an algorithm to find out whether there is a route between two nodes. ...

  2. [CareerCup] 4.2 Route between Two Nodes in Directed Graph 有向图中两点的路径

    4.2 Given a directed graph, design an algorithm to find out whether there is a route between two nod ...

  3. [LintCode]——目录

    Yet Another Source Code for LintCode Current Status : 232AC / 289ALL in Language C++, Up to date (20 ...

  4. BFS vs DFS

    1 Clone Graph   1  copy ervery nodes by bfs  2  add neighbors public UndirectedGraphNode cloneGraph( ...

  5. HDU 4240 Route Redundancy

    Route Redundancy Time Limit: 1000ms Memory Limit: 32768KB This problem will be judged on HDU. Origin ...

  6. HDU 2454 Degree Sequence of Graph G(Havel定理 推断一个简单图的存在)

    主题链接:pid=2454">http://acm.hdu.edu.cn/showproblem.php?pid=2454 Problem Description Wang Haiya ...

  7. 深度学习在graph上的使用

    原文地址:https://zhuanlan.zhihu.com/p/27216346 本文要介绍的这一篇paper是ICML2016上一篇关于 CNN 在图(graph)上的应用.ICML 是机器学习 ...

  8. Hdoj 2454.Degree Sequence of Graph G 题解

    Problem Description Wang Haiyang is a strong and optimistic Chinese youngster. Although born and bro ...

  9. Echarts中graph类型的运用求教

    以下是百度Echarts官网上关系图的源码,但是这个关系图的node节点和edge都是静态文件里规定好的,我现在想动态实现,点击其中一个节点A然后新产生一个新节点B,并且有A和B之间的edge,就类似 ...

随机推荐

  1. w-BIG TABLE-view+where-small table

    w-BIG TABLE DROP PROCEDURE IF EXISTS truncate_insert_sales_rank_toparow_month; DELIMITER /w/ CREATE ...

  2. php javascript C 变量环境 块级作用域

    <?php $w = 'w'; $wb = '123'.$w; $w = 'ww'; echo $wb; if(TRUE){ $wd = '123wd'; } echo $wd; if(FALS ...

  3. 【转】如何使php的MD5与C#的MD5一致?

    有c#生成MD5的代码如下: class CreateMD5 { static void Main(string[] args) { string source = "提问指南"; ...

  4. svn截图

        一.合并一个范围的版本 此类型应用最为广泛,主要是把分支中的修改合并到主干上来.在主干上点击右键选择合并,然后选择合并类型:合并一个范围的版本.合并的源URL填写的是要合并的分支的URL,待合 ...

  5. (IOS)Swift2.0 Radio 程序分析

    本文主要分享下楼主在学习Swift编程过程中,对GitHub上的一个开源项目Swift Radio的研究心得. 项目地址:https://github.com/swiftcodex/Swift-Rad ...

  6. ssh2 php扩展

    如何通过PHP启动和关闭远程服务器上的某个软件,譬如Memcached.对于俺这个刚刚掌握PHP编程皮毛的菜鸟来说,最直接不过的想法就是用exec函数执行SSH命令呗,先把运行Apache+PHP的服 ...

  7. QWidget 键盘事件 焦点(QApplication源码)

    在Qt中,键盘事件和QWidget的focus密不可分:一般来说,一个拥有焦点(focus)的QWidget或者grabKeyboard()的QWidget才可以接受键盘事件. 键盘事件派发给谁? 如 ...

  8. 转:php 获取时间今天明天昨天时间戳

    <?php echo "今天:".date("Y-m-d")."<br>"; echo "昨天:".d ...

  9. Mysql 按行dump出数据

    mysqldump -u${user} -p${passwd} --skip-extended-insert --database ${dbname} --table ${tablename} > ...

  10. interview review

    缘起: 因为最近要找工作,自己总结了一下面试的注意事项. 1自我介绍方法 1.基本情况:姓名.年龄.学历.家庭与理想. 简单明了,不要啰嗦. 2.学习能力:专业知识.勤奋好学. 用事实说明学习能力不错 ...