[PAT] 1142 Maximal Clique(25 分)
1142 Maximal Clique(25 分)
A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the clique are adjacent. A maximal clique is a clique that cannot be extended by including one more adjacent vertex. (Quoted from https://en.wikipedia.org/wiki/Clique_(graph_theory)
Now it is your job to judge if a given subset of vertices can form a maximal clique.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers Nv (≤ 200), the number of vertices in the graph, and Ne, the number of undirected edges. Then Ne lines follow, each gives a pair of vertices of an edge. The vertices are numbered from 1 to Nv.
After the graph, there is another positive integer M (≤ 100). Then M lines of query follow, each first gives a positive number K (≤ Nv), then followed by a sequence of K distinct vertices. All the numbers in a line are separated by a space.
Output Specification:
For each of the M queries, print in a line Yes if the given subset of vertices can form a maximal clique; or if it is a clique but not a maximal clique, print Not Maximal; or if it is not a clique at all, print Not a Clique.
Sample Input:
8 10
5 6
7 8
6 4
3 6
4 5
2 3
8 2
2 7
5 3
3 4
6
4 5 4 3 6
3 2 8 7
2 2 3
1 1
3 4 3 6
3 3 2 1
Sample Output:
Yes
Yes
Yes
Yes
Not Maximal
Not a Clique
题意:
clique是一个无向图的点的子集,clique里每两个不同的点都是相连的。最大clique是不能扩展更多相连点的clique。
判断给定的点的子集是否为一个最大的clique。
思路:
将输入存在一个二维数组(矩阵)内,对于每一个查询,先判断是否为clique(每两个点对应的二维数组为1),再判断是否为max clique(遍历给定点之外的点是否和给定的点都有连线)。
题解:
#include<cstdlib>
#include<cstdio>
#include<vector>
using namespace std;
][];
int main() {
int nv, ne, m;
scanf("%d %d", &nv, &ne);
; i < ne; i++) {
int a, b;
scanf("%d %d", &a, &b);
vertex[a][b] = vertex[b][a] = ;
}
scanf("%d", &m);
; i < m; i++) {
int k;
scanf("%d", &k);
vector<);
vector<int> verts;
; j < k; j++) {
int t;
scanf("%d", &t);
verts.push_back(t);
v[t] = true;
}
//判断是否为clique
//只要给定查询中的每两个点对应矩阵上的值为0,说明它不是clique
bool isClique = true;
; j < verts.size(); j++) {
; r < verts.size(); r++) {
) {
printf("Not a Clique\n");
isClique = false;
break;
}
}
if (!isClique) break;
}
if (!isClique) continue;
//如果是clique,
//并且还存在给定之外的点与给定的所有点对应矩阵的值为1
//说明其不是max clique
bool notMaximal = false;
; j <= nv; j++) {
if (v[j] == true) continue;
bool isMaxClique = false;
; r < verts.size(); r++) {
) {
isMaxClique = true;
break;
}
}
if (!isMaxClique) {
printf("Not Maximal\n");
notMaximal = true;
break;
}
}
if (!notMaximal) printf("Yes\n");
}
;
}
[PAT] 1142 Maximal Clique(25 分)的更多相关文章
- PAT 1142 Maximal Clique[难]
1142 Maximal Clique (25 分) A clique is a subset of vertices of an undirected graph such that every t ...
- PAT 1142 Maximal Clique
A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...
- 1142. Maximal Clique (25)
A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...
- PTA PAT排名汇总(25 分)
PAT排名汇总(25 分) 计算机程序设计能力考试(Programming Ability Test,简称PAT)旨在通过统一组织的在线考试及自动评测方法客观地评判考生的算法设计与程序设计实现能力,科 ...
- PAT A1142 Maximal Clique (25 分)——图
A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...
- PAT 甲级 1142 Maximal Clique
https://pintia.cn/problem-sets/994805342720868352/problems/994805343979159552 A clique is a subset o ...
- PAT 甲级 1078 Hashing (25 分)(简单,平方二次探测)
1078 Hashing (25 分) The task of this problem is simple: insert a sequence of distinct positive int ...
- PAT 甲级 1070 Mooncake (25 分)(结构体排序,贪心,简单)
1070 Mooncake (25 分) Mooncake is a Chinese bakery product traditionally eaten during the Mid-Autum ...
- PAT 甲级 1032 Sharing (25 分)(结构体模拟链表,结构体的赋值是深拷贝)
1032 Sharing (25 分) To store English words, one method is to use linked lists and store a word let ...
随机推荐
- Visio分类
以编程方式使用 Microsoft Office Visio 2003 ActiveX 控件 visio应用程序相关设置-选项-视图 visio应用程序相关设置-选项-常规 visio中相关设置-菜单 ...
- 洛谷 P3952 时间复杂度 解题报告
P3952 时间复杂度 题目描述 小明正在学习一种新的编程语言A++,刚学会循环语句的他激动地写了好多程序并 给出了他自己算出的时间复杂度,可他的编程老师实在不想一个一个检查小明的程序, 于是你的机会 ...
- ACM2066
题目原址:http://acm.hdu.edu.cn/showproblem.php?pid=2066 大神必须飘过,我在这个题目里面学到了太多太多了.我提交了十六次,错了十二次,反复了这么久才解决内 ...
- [技巧篇]12.从Spring的编码过滤器说起
有一枚学生问问了我一个问题,突然灵感爆发,他使用的Spring的过滤器,前台利用GET方式向后端发出一个请求,由于里面含有中文数据,结果在后端显示的是乱码,他问我为什么?明明在Spring里面也配了字 ...
- [技巧篇]04.使用PowerDesigner逆向生成
- NOI2001 方程的解数
1735 方程的解数 http://codevs.cn/problem/1735/ 2001年NOI全国竞赛 时间限制: 5 s 空间限制: 64000 KB 题目描述 Descripti ...
- 51Nod 1095 Anigram单词 | Hash
Input示例 5 add dad bad cad did 3 add cac dda Output示例 1 0 2 题意:一系列字符串,查询字符串S,能通过其他字符串交换串内字符顺序得到的字符串个数 ...
- \(\rm LightOJ 1371 - Energetic Pandas 简单计数+组合\)
http://www.lightoj.com/volume_showproblem.php?problem=1371 题意:给你n根竹子,和n只熊猫(XD),每个熊猫只能选择重量不大于它的竹子,问有几 ...
- Bzoj4873 [SXOI2017]寿司餐厅
Time Limit: 20 Sec Memory Limit: 512 MBSubmit: 64 Solved: 45 Description Kiana最近喜欢到一家非常美味的寿司餐厅用餐.每 ...
- 【POJ】1222 EXTENDED LIGHTS OUT(高斯消元)
http://poj.org/problem?id=1222 竟然我理解了两天..... 首先先来了解异或方程组(或者说mod2方程组,modk的话貌似可以这样拓展出来) 对于一些我们需要求出的变量a ...