30. Substring with Concatenation of All Words

Problem's Link

----------------------------------------------------------------------------

Mean:

给你一个字符串s,和一个字符串集合words,找出s中words所有单词连续出现的起始下标.

analyse:

思路:窗口滑动算法.

枚举所有长度为words[0].length()的子串,然后使用窗口滑动算法来统计.

Trick:集合words是一个可重集,当连续出现的单词书大于words中的时,需要回退删除开头部分的单词,注意细节.

Time complexity: O(N)

view code

|| ) ; ; ;
           ;
                   left = j + wl;
               }
           }
       }
       return ans;
   }
};

LeetCode - 30. Substring with Concatenation of All Words的更多相关文章

  1. [LeetCode] 30. Substring with Concatenation of All Words 解题思路 - Java

    You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...

  2. leetCode 30.Substring with Concatenation of All Words (words中全部子串相连) 解题思路和方法

    Substring with Concatenation of All Words You are given a string, s, and a list of words, words, tha ...

  3. [LeetCode] 30. Substring with Concatenation of All Words 串联所有单词的子串

    You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...

  4. Java [leetcode 30]Substring with Concatenation of All Words

    题目描述: You are given a string, s, and a list of words, words, that are all of the same length. Find a ...

  5. [leetcode]30. Substring with Concatenation of All Words由所有单词连成的子串

    You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...

  6. LeetCode 30 Substring with Concatenation of All Words(确定包含所有子串的起始下标)

    题目链接: https://leetcode.com/problems/substring-with-concatenation-of-all-words/?tab=Description   在字符 ...

  7. [LeetCode] 30. Substring with Concatenation of All Words ☆☆☆

    You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...

  8. [Leetcode][Python]30: Substring with Concatenation of All Words

    # -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 30: Substring with Concatenation of All ...

  9. LeetCode HashTable 30 Substring with Concatenation of All Words

    You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...

随机推荐

  1. python排序算法的实现-插入

    1.算法: 设有一组关键字{ K 1 , K 2 ,…, K n }:排序开始就认为 K 1 是一个有序序列:让 K 2 插入上述表长为 1 的有序序列,使之成为一个表长为 2 的有序序列:然后让 K ...

  2. gem install 出现Errno::ECONNRESET: Connection reset by peer - SSL_connect (https://api.rubygems.org

    在安装了rvm来管理多版本的ruby之后,想在不同环境下安装一些gems,结果gem install puma 之后,发现一次又一次失败. gem install 出现Errno::ECONNRESE ...

  3. 在Window下安装Oracle 12C Cloud Control Agent

    ① 准备好安装源,这个ORACLE普通账号无法下载到,有需要的可以联系我   p14570373_112000_Generic.zip,用于Windows 64位操作系统 ② 解压p14570373_ ...

  4. Mac系统下,在android studio中使用Github版本管理

    1.下载并安装github客户端http://git-scm.com/download/ 2.打开android studio,测试github是否使用ok 点击"test",如果 ...

  5. Excel的一些常用设置

    1. Freeze表头 (1) 下拉Worksheet的Pane,让该sheet有2个工作区,将该pane下拉到某一特定的行. (2)Window->Freeze Panes.此时会将pane智 ...

  6. CreateProcessAsUser,C#写的windows服务弹框提示消息或者启动子进程

    服务(Service)对于大家来说一定不会陌生,它是Windows 操作系统重要的组成部分.我们可以把服务想像成一种特殊的应用程序,它随系统的“开启-关闭”而“开始-停止”其工作内容,在这期间无需任何 ...

  7. joomla allvideo 去掉embed share

    文件位置plugins/content/jw_allvideos/jw_allvideos/includes/sources.php找到以下代码 jwplayer('avID_{SOURCEID}') ...

  8. C# 类型基础——你可能忽略的技术细节

    引言 本文之初的目的是讲述设计模式中的 Prototype(原型)模式,但是如果想较清楚地弄明白这个模式,需要了解对象克隆(Object Clone),Clone 其实也就是对象复制.复制又分为了浅度 ...

  9. 判断JavaScript对象为null或者属性为空

    http://blog.csdn.net/yiluoak_47/article/details/7766760 首先说下null与undefined区别: 对已声明但未初始化的和未声明的变量执行typ ...

  10. Java框架篇---Mybatis 入门

    一.Mybatis介绍 MyBatis是一款一流的支持自定义SQL.存储过程和高级映射的持久化框架.MyBatis几乎消除了所有的JDBC代码,也基本不需要手工去设置参数和获取检索结果.MyBatis ...