POJ2533Longest Ordered Subsequence(DP)
http://poj.org/problem?id=2533
在经典不过的DP题目了。。。。

#include <map>
#include <set>
#include <stack>
#include <queue>
#include <cmath>
#include <ctime>
#include <vector>
#include <cstdio>
#include <cctype>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;
#define INF 0x3f3f3f3f
#define MAX(a,b) (a > b ? a : b)
#define MIN(a,b) (a < b ? a : b)
#define mem0(a) memset(a,0,sizeof(a)) typedef long long LL;
const double eps = 1e-;
const int MAXN = ;
const int MAXM = ; int DP[], a[], N; int BinarySearch(int low, int high, int val)
{
while(low < high)
{
int mid = (low + high) >> ;
if(DP[mid] < val) low = mid +;
else high = mid;
}
return low;
} int main()
{
while(~scanf("%d", &N))
{
for(int i=;i<=N;i++)
{
scanf("%d", &a[i]);
}
DP[] = a[];
int len = ;
for(int i=;i<=N;i++)
{
int id = BinarySearch(, len+, a[i]);
DP[id] = a[i];
if(id > len) ++len;
}
printf("%d\n", len);
}
return ;
}
POJ2533Longest Ordered Subsequence(DP)的更多相关文章
- poj2533--Longest Ordered Subsequence(dp:最长上升子序列)
Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 33943 Acc ...
- POJ 2533-Longest Ordered Subsequence(DP)
Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 34454 Acc ...
- POJ 2533——Longest Ordered Subsequence(DP)
链接:http://poj.org/problem?id=2533 题解 #include<iostream> using namespace std; ]; //存放数列 ]; //b[ ...
- POJ 2533 Longest Ordered Subsequence(DP 最长上升子序列)
Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 38980 Acc ...
- POJ 2533 Longest Ordered Subsequence(dp LIS)
Language: Default Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submis ...
- Poj 2533 Longest Ordered Subsequence(LIS)
一.Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequenc ...
- poj-2533 longest ordered subsequence(动态规划)
Time limit2000 ms Memory limit65536 kB A numeric sequence of ai is ordered if a1 < a2 < ... &l ...
- HPU第三次积分赛-D:Longest Increasing Subsequence(DP)
Longest Increasing Subsequence 描述 给出一组长度为n的序列,a1,a2,a3,a4...an, 求出这个序列长度为k的严格递增子序列的个数 输入 第一行输入T ...
- HDU 1159 Common Subsequence (dp)
题目链接 Problem Description A subsequence of a given sequence is the given sequence with some elements ...
随机推荐
- 51nod1556 计算
ans[n]=ans[n-1]*3-m[n-2];YY一下可以懂的.减掉的就是往下走的情况不符合正整数的情况.m是默慈金数. #include<cstdio> #include<cs ...
- 【转】Android 服务器之SFTP服务器上传下载功能
原文网址:http://blog.csdn.net/tanghua0809/article/details/47056327 本文主要是讲解Android服务器之SFTP服务器的上传下载功能,也是对之 ...
- Linux/Unix shell 监控Oracle监听器(monitor listener)
使用shell脚本实现对Oracle数据库的监控与管理将大大简化DBA的工作负担,如常见的对实例的监控,监听的监控,告警日志的监控,以及数据库的备份,AWR report的自动邮件等.本文给出Linu ...
- 简单的聊天程序,主要用到的是Socket
服务端: import java.io.*; import java.net.*; import java.util.*; public class ChatServer { boolean stat ...
- linux ubuntu 安装jdk
junluobj@junluobj:~$sudo mkdir /usr/lib/jvmwww.linuxidc.com@linuxidc:~$tar zvxf jdk-8u20-linux-x64.t ...
- Android中垃圾回收日志信息
原因 GC_CONCURRENTfreed 178K, 41% free 3673K/6151K, external 0K/0K, paused 2ms+2msGC_EXPLICITfreed 6K, ...
- ajax连接池和XMLHttpRequest
连接池 我们公司在路由和交换机web界面和后端交互全部采用的是自己封装的ajax组件完成的,组件有点老了,代码风格和其中的某些用法现在看起来都有点不习惯.今天把这个组件的核心部分的ajax连接池记录下 ...
- 单机版搭建Hadoop环境图文教程详解
安装过程: 一.安装Linux操作系统二.在Ubuntu下创建hadoop用户组和用户三.在Ubuntu下安装JDK四.修改机器名五.安装ssh服务六.建立ssh无密码登录本机七.安装hadoop八. ...
- cdh5.4、cm5.4 安装详细步骤
安装准备: 1.centos6.5 64位 虚拟机,内存分配4G.硬盘位20G 2.cm5.4 cdh5.4 包 安装步骤 一.centos安装完后,进行系统配置 1.关闭防火墙 service ip ...
- mvc中@RenderSection()研究
一.@RenderSection定义 HelperResult RenderSection(string name) 但是当如果使用了_Layout.cshtml做母版页的页没有实现Section的话 ...