题意:给定一个数组,求最小的字数组使得数组里存在至少一对重复元素

题解:每个点求出他的后继在哪,然后每次贪心就这个点到他的后继为一个子数组,求出最小的就是答案

#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<string>
#define ll long long
using namespace std;
int T,n,ans;
int a[],nxt[],hd[];
int main()
{
scanf("%d",&T);
while(T--)
{
for(int i=;i<=n;i++)hd[i]=nxt[i]=;
scanf("%d",&n);
for(int i=;i<=n;i++){scanf("%d",&a[i]);nxt[i]=hd[a[i]];hd[a[i]]=i;}
ans=1e9;
for(int i=;i<=n;i++)if(nxt[i])ans=min(ans,i-nxt[i]+);
printf(ans==1e9?"-1\n":"%d\n",ans);
}
return ;
}

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